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Leokris [45]
2 years ago
15

How many moles of nh3 can be produced from 15.0 mol of h2 and excess n2?

Chemistry
1 answer:
PSYCHO15rus [73]2 years ago
5 0
First, we have to write a balanced equation for the production of ammonia (NH₃) from hydrogen gas (H₂) and nitrogen gas (N₂):
                    N₂   +   3H₂   →   2NH₃

Now, the mole ratio of H₂ : NH₃ is 3 : 2 based on the coefficients of the balanced equation.

If the moles of H₂ = 15 moles

   then the moles of NH₃ produced = (15 mol ÷ 3) × 2 
                                                          =  10 mol

Thus, the number of moles of NH₃ produced when 15 mol of hydrogen gas is combined with excess nitrogen gas is 10 mol.
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lorasvet [3.4K]

I would say the answer is D

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The most direct way to probe the vibrational frequencies of a molecule is through infrared spectroscopy. This is because vibrational transitions typically require an amount of energy that corresponds to the infrared region of the spectrum. Raman spectroscopy, which typically uses visible light, can also be used to directly measure vibration frequencies.

7 0
2 years ago
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Find the density of an object that has a mass of 6.13 g and volume of 1.50 cm³.​
storchak [24]
  • <em>Answer:</em>

<em>≈ 4.10 g/cm³</em>

  • <em>Explanation:</em>

<em>Hi there ! </em>

<em><u /></em>

<em><u>Density formula</u></em>

<em>d = m/V</em>

<em>d = 6.13g/1.5cm³</em>

<em>d = 4.08(6) g/cm³ ≈ 4.10 g/cm³</em>

<em />

<em>Good luck !</em>

8 0
3 years ago
Identify and calculate the number of representative particles in 2.15 moles of gold.<br>​
LekaFEV [45]

Answer:

1.29 * 10^{24} particles of gold

Explanation:

To convert the number of moles of any substance, in this case gold, you need Avogadro's number.

Avogadro's number is always 6.022 × 10^{23}

2.15 moles Au × \frac{6.022*10^{23} particles}{1 mole Au} = 1.29 * 10^{24} particles of gold

5 0
2 years ago
Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 264 mL .
gavmur [86]
The formula for density is:

D = m/v

We can use the formula to figure out the mass because we already know two of the three values (we are given the density and volume), so we only have to solve for <em>m. </em>If we plug our given values into the formula, we get:

2.70 = m / 264

Now, all we need to do is solve for <em>m</em>. The goal is to get <em>m</em> on one side of the equation, and all we have to do is multiply each side of the equation by 264:

264 × 2.70 = (m÷264) × 264

264 × 2.70 = m

m = 712.8

The mass of the piece of aluminum is 712.8 grams.
4 0
3 years ago
What layers are composed of metals? Choose all that apply.<br> Inner core<br> Outer core<br> Mantle
svlad2 [7]

Answer:

to be honest ask your teacher

3 0
1 year ago
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