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mars1129 [50]
1 year ago
8

What is the empirical formula for the molecular formula given? Molecular formula: C5H12O

Chemistry
1 answer:
Semenov [28]1 year ago
7 0

What is the empirical formula for the molecular formula given? Molecular formula: C5H12O

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In chemistry what is Faraday's law​
Eduardwww [97]

Answer:

<u><em>Faraday’s – First Law of Electrolysis</em></u>

<u><em>It is one of the primary laws of electrolysis. It states, during electrolysis, the amount of chemical reaction which occurs at any electrode under the influence of electrical energy is proportional to the quantity of electricity passed through the electrolyte.</em></u>

<u><em></em></u>

<u><em>Faraday’s – Second Law of Electrolysis</em></u>

<u><em>Faraday’s second law of electrolysis states that if the same amount of electricity is passed through different electrolytes, the masses of ions deposited at the electrodes are directly proportional to their chemical equivalents.</em></u>

<u><em></em></u>

<u><em>From these laws of electrolysis, we can deduce that the amount of electricity needed for oxidation-reduction depends on the stoichiometry of the electrode reaction.</em></u>

<u><em>The product of an electrolytic reaction depends on the nature of the material being electrolysed and the type of electrodes used. In the case of an inert electrode such as platinum or gold, the electrode does not participate in the chemical reaction and acts only as a source or sink for electrons. While, in the case of a reactive electrode, the electrode participates in the reaction.</em></u>

<u><em></em></u>

<u><em>Hence, different products are obtained for electrolysis in the case of reactive and inert electrodes. Oxidizing and reducing species present in the electrolytic cell and their standard electrode potential too, affect the products of electrolysis.</em></u>

<u><em></em></u>

<u><em>FAQs</em></u>

<u><em>1. What’s a Faraday?</em></u>

<u><em>Ans: The Faraday is an electric charge volume unit without measurements, equal to approximately 6.02 x 10 23 electric charge carriers.</em></u>

<u><em></em></u>

<u><em>2. Why is Faraday’s law important?</em></u>

<u><em>A shifting magnetic flux creates an electric field, according to Faraday’s law. Faraday’s law is particularly important since it addresses the connection of the E-field and the B-field and understands that this connection necessitates flux fluctuation over time.</em></u>

<u><em></em></u>

<u><em>3. How does electrolysis remove rust?</em></u>

<u><em>Ans: Electrolysis is a method of removing iron oxide by passing a small electrical charge through the rusty metal from a battery or battery charger to induce ion exchange while the device is submerged in an electrolyte solution.</em></u>

<u><em></em></u>

<u><em>4. What happens to water during electrolysis?</em></u>

<u><em>Ans: Water’s Electrolysis. By passing an electrical current through it, water can be decomposed. When this happens, an oxidation-reduction reaction is caused by the electrons from the electric current.</em></u>

<u><em></em></u>

<u><em>5. What is the negative electrode called in electrolysis?</em></u>

<u><em>Ans: Through electrolysis, the negatively charged electrode is called the cathode. The positively charged electrode is called the anode in electrolysis. Negatively charged ions are moving towards the anode.</em></u>

<u><em></em></u>

<em>Hope it helps!</em>

5 0
2 years ago
Read 2 more answers
What is the molarity of solution obtained when 5.71 g of sodium carbonate-10-water is dissolved in water and made up to 250.0 cm
disa [49]

We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.

The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O)  is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³

The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.

Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.

5.71 grams of Na₂CO₃.10 H₂O is equal to \frac{5.71}{286}= 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.

Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is \frac{0.0199 X 1000}{250} = 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³


3 0
3 years ago
Asprin can be made by adding 200.0 g of salicylinc
damaskus [11]
Correct, Was that a question.
7 0
3 years ago
Name the compound P4O10
Delvig [45]
I believe the compound is Phosphorus pentoxide
6 0
3 years ago
Read 2 more answers
PLEASE HELP
neonofarm [45]

Answer:

The answer to your question is 0.10 M

Explanation:

Data

Molarity = ?

mass of Sucrose = 125 g

volume = 3.5 l

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of sucrose

C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

               = 144 + 22 + 176

               = 342 g

2.- Convert the mass of sucrose to moles

                  342 g of sucrose ------------------- 1 mol

                  125 g of sucrose -------------------- x

                           x = (125 x 1) / 342

                           x = 0.365 moles

3.- Calculate the molarity

Molarity = 0.365 / 3.5

4.- Result

Molarity = 0.10

5 0
3 years ago
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