The mean radius of the sun is 432,450 miles (696,000 kilometers), which makes its diameter about 864,938 miles (1.392 million km). You could line up 109 Earths across the face of the sun. The sun's circumference is about 2,713,406 miles (4,366,813 km). The total volume of the sun is 1.4 x 1027 cubic meters.
Answer: The correct answer is option D.
Explanation: Super-giant stars are the stars which are greater than Sun. They have a mass hundred time greater than Sun and can be thousand times greater than Sun.
The masses of the stars are represented in Solar masses which is the mass of the Sun.
Mass of Betelgeuse = 20 Solar masses
Mass of Pollux = 1.7 Solar masses
Mass of Sirius = 2.02 Solar masses
Mass of Sun = 1 Solar mass.
As, the mass of Sun is the least from the given stars. Hence, it is least considered as a super-giant.
1.) The modern atomic theory has been updated over the years..
the correct option is:
C. The changes make the theory stronger because it has been tested and edited multiple times, making it more durable.
2. In Rutherfords experiment,Based on Thomson's plum pudding model of the atom, what did Rutherford expect to happen;
A. All the alpha particles would be deflected by the foil because of the even distribution of mass and charge throughout the atom.
According to Thomson's plum pudding model of the atom the positive and negative charges are evenly distributed.
Answer:
17.86mL of the HCl solution
Explanation:
The reaction of CaCO₃ with HCl is:
CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O
The concentration of HCl with a pH of 1.52 is:
pH = 1.52 = -log [H⁺]
[H⁺] = 0.0302M = [HCl]
27.0mg = 0.0270g of CaCO₃ (Molar mass: 100.09g/mol) are:
0.0270g of CaCO₃ ₓ (1mol / 100.09g) = <em>2.70x10⁻⁴ moles of CaCO₃</em>
Moles of HCl to react completely with these moles of CaCO₃ are:
2.70x10⁻⁴ moles of CaCO₃ ₓ (2 mol HCl / 1 mol CaCO₃) =
5.40x10⁻⁴ moles of HCl
As the concentration of HCl is 0.0302M, volume in 5.40x10⁻⁴ moles is:
5.40x10⁻⁴ moles of HCl * (1L / 0.0302mol) = 0.01786L =
<h3>17.86mL of the HCl solution</h3>
Answer:
6.25 g of Carbon is in Excess
Explanation:
The balance chemical equation is as follow:
C + O₂ → CO₂
Step 1: Calculate Moles of O₂ as:
Moles = Mass / M/Mass
Moles = 50 g / 32 g/mol
Moles = 1.562 mol of O₂
Step 2: Calculate Moles of C as;
Moles = 25 g / 12 g/mol
Moles = 2.08 mol
Step 3: Calculate the Limiting reagent:
According to equation,
1 moles of O₂ reacted with = 1 mole of C
So,
1.562 moles of O₂ will react with = X moles of C
Solving for X,
X = 1 mol × 1.562 mol / 1 mol
X = 1.562 mol of C
While we are provided with 2.08 mol of C. Means C is in excess.
Step 4: Calculate amount of Excess C as;
Excess Moles = Given Moles - Used Moles
Excess Moles = 2.08 mol - 1.562 mol
Excess Moles = 0.521 moles
Step 5: Converting Excess moles to Mass as:
Mass = Moles × M.Mass
Mass = 0.521 mol × 12 g/mol
Mass = 6.25 g
