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DedPeter [7]
10 months ago
5

Given:m<6=m<8b l l cprove:a l l b

Mathematics
2 answers:
pochemuha9 months ago
6 0
The other person who answered should be right!
makvit [3.9K]9 months ago
5 0

1) From the data, we can see that

\angle6=\angle8

is given.

2) Next,

\angle6=\angle7

since they are alternate angles.

3) By substitution, these means that

\angle7=\angle8

4) Finally, a || b since

\angle7=\angle8

this is because, angle 7 and angle 8 are corresponding angles.

Corresponding angles are angles that are on the same corner at each intersection. For instance, 2 and 6

4 and 8, 1 and 5, 3 and 7

In our case, 7 and 8 are corresponding angles

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Factories A and B produce computers. Factory A produces 3 times as many computers as factory B. The probability that an item pro
OleMash [197]

Answer:

P(A∣D) = 0.667

Step-by-step explanation:

We are given;

P(A) = 3P(B)

P(D|A) = 0.03

P(D|B) = 0.045

Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.

Using Bayes' Rule and Law of Total Probability, we will get;

P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]

Plugging in the relevant values, we have;

P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]

P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]

P(B) will cancel out to give;

P(A∣D) = 0.09/0.135

P(A∣D) = 0.667

7 0
3 years ago
Helppppppppppppppppppp
GaryK [48]

shovels=3

bucket =7

a_ 3:7

b- 7:3

8 0
2 years ago
Find the area for a trapezoid 9.85 m 15 m 11 m 9 m
igor_vitrenko [27]

Answer:

total area = 99m² + 39.4m²

= 138.4m²

7 0
2 years ago
What is 4*54<br> brainiest
nirvana33 [79]

Answer:

2 x54 + 2 x 54

108 + 108

216

Step-by-step explanation:

8 0
3 years ago
A population of 200 animals is decreasing by a rate of .96 per year . At this rate, in how many years will the population be les
mojhsa [17]
At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ

Now, we need to know when the population will be less than 170.

So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n

n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
7 0
3 years ago
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