Answer:
B
Explanation:
Because , it is the answer .
Lewis structures are diagrams that show the bonding between
atoms of molecule and the lone pairs of electrons that may exist in the
molecule. Phosphoryl iodide is used in the preparation of organophosphorus
derivatives and phosphate esters. The Lewis structure of POI3 is:
Answer:
The molecular formula of the compound is .
Explanation:
Given empirical formula of the compound is .
Atomic mass of carbon = 12 u
Atomic mass of hydrogen = 1 u
Atomic mass of oxygen = 16 u
Empirical formula mass of compound =
Molecular mass of compound = 176 g/mol
Molecular formula = n Empirical formula
Molecular formula = 4
Molecular formula of the compound is
Answer:
H2
Explanation:
CO2 + H2 → CO + H2O
↓ (-2). 0. (+2 )(-2). (+1)(-2)
↓ ·2 (+2)
+4 (-4)
Write down the oxidation number under each element, each molecule should equal 0 unless there is a charge shown.
Oxygen, always has an oxidation number of -2 unless in a peroxide.
Hydrogen, is -1 with metals,+1 with non-metals. Hydrogen loves non-metals!
H2 is zero because any standalone element has an oxidation number of zero
What is being oxidized? Whatever is being oxidized, loses electrons and becomes more positive, it will be a whole molecule, not just an element. In this case, the H in H2 goes from 0 to (+1) so it is the oxidized molecule.
Answer:
In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.
Explanation:
Step 1: Data given
Mass of HCl = 69.0 grams
Mass of Al = 78.0 grams
Molar mass HCl = 36.46 g/mol
Atomic mass Al = 26.99 g/mol
Step 2: The balanced equation
6HCl(aq) + 2Al(s) → 3H2(g) + 2AlCl3(s)
Step 3: calculate moles HCl
Moles HCl = mass HCl / molar mass HCl
Moles HCl = 69.0 grams / 36.46 g/mol
Moles HCl = 1.89 moles
Step 4: Calculate moles Al
Moles Al = 78.0 grams / 26.99 g/mol
Moles Al = 2.89 moles
Step 5: Calculate the limiting reactant
For 6 moles HCl we need 2 moles Al to produce 3 moles H2 and 2 moles AlCl3
HCl is the limiting reactant. It will completely be consumed (1.89 moles). Aluminium is the reactant in excess. There will react 1.89 / 3 = 0.63 moles
There will remain 2.89 - 0.63 = 2.26 moles aluminium
In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.