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Lady bird [3.3K]
1 year ago
8

How are large polymers formed? by repetitive combinations of simple subunits by the addition of halogens to a small molecule by

combining a few different and larger molecules by combining many different and smaller molecules
Chemistry
1 answer:
Gre4nikov [31]1 year ago
6 0

Answer:

How are large polymers formed? by repetitive combinations of simple subunits by the addition of halogens to a small molecule by combining a few different and larger molecules by combining many different and smaller molecules

Explanation:

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Draw the bridged bromonium ion that is formed as an intermediate during the bromination of this alkene. include hydrogen atoms,
gogolik [260]
<h2>Answer</h2>

Bromination:

Any reaction or process in which bromine (and no other elements) are introduced into a molecule.

Bromonium Ion:

The bromonium ion is formed when alkenes react with bromine. When the π cloud of the alkene (acting as a nucleophile) approaches the bromine molecule (acting as an electrophile), the σ-bond electrons of Br2 are pushed away, resulting in the departure of the bromide anion.(2)

Mechanism:

Step 1:

In the first step of the reaction, a bromine molecule approaches the electron-rich alkene carbon–carbon double bond. The bromine atom closer to the bond takes on a partial positive charge as its electrons are repelled by the electrons of the double bond. The atom is electrophilic at this time and is attacked by the pi electrons of the alkene [carbon–carbon double bond]. It forms for an instant a single sigma bond to both of the carbon atoms involved (2). The bonding of bromine is special in this intermediate, due to its relatively large size compared to carbon, the bromide ion is capable of interacting with both carbons which once shared the π-bond, making a three-membered ring. The bromide ion acquires a positive formal charge. At this moment the halogen ion is called a "bromonium ion".

Step 2:

When the first bromine atom attacks the carbon–carbon π-bond, it leaves behind one of its electrons with the other bromine that it was bonded to in Br2. That other atom is now a negative bromide anion and is attracted to the slight positive charge on the carbon atoms. It is blocked from nucleophilic attack on one side of the carbon chain by the first bromine atom and can only attack from the other side. As it attacks and forms a bond with one of the carbons, the bond between the first bromine atom and the other carbon atoms breaks, leaving each carbon atom with a halogen substituent.

In this way the two halogens add in an anti addition fashion, and when the alkene is part of a cycle the dibromide adopts the trans configuration.

6 0
3 years ago
This diagram shows the forces acting on a car. The center dot represents the car, and the arrows represent the forces acting on
Mariulka [41]

Answer : The correct option is B- Towards the left.

Solution : Given,

Force on car in upward direction, F_1 = 6000 N

Force on car in downward direction, F_2 = 6000 N

Force on car in right direction, F_3 = 5000 N

Force on car in left direction, F_4 = 6000 N

Force : Force is equal to the mass multiplied by the acceleration. The force is directly proportional to the acceleration.

Formula :  F =  m × a

where, F is force, m is mass and a is acceleration.

From the given diagram we conclude that the F_1 and F_2 are in opposite direction and the force acting on car are same. So, their net force is zero.

And in case of F_3 and F_4, the net force will not be zero because force acting on car are different. The car will accelerate towards left direction because F_4 is higher than the F_3.

So, the car will accelerate towards left direction.


3 0
2 years ago
Calculate the percentage mass of hydrogen in hydrochloric acid, HCI​
PIT_PIT [208]

Answer:

To find the mass percent of hydrogen in hydrogen chloride, we must divide the weight of the hydrogen atom alone by the weight of the entire molecule. Then we multiply by 100% to find the percentage. Thus, 2.77% of the mass of hydrogen chloride is hydrogen.

Explanation:

i hope you understand better

4 0
2 years ago
2. Calculate the joules of energy required to heat 454.3g of water<br> frum 5.4°C to 98.6°C.
Tasya [4]

Answer:

176984.38J

Explanation:

E = mC∆T

Where E is the energy in joules

M is the mass of water

C is the specific heat capacity of water =4.184J/g°C

It is known that it will take 4.184J of energy to change the temperature of water by one degree Celsius.

∆T = 98.6°c - 5.4°c

= 93.2°c

∆H = 454.3g × 4.18J/g°C × 93.2°c

= 176984.3768

176984.38J

7 0
3 years ago
The bonds of oxygen molecules are broken by sunlight. The minimum energy required to break the oxygen-oxygen bond is 495 kJ/mol
olga_2 [115]

Answer:

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

Explanation:

Energy required to break the 1 mol oxygen-oxygen bond:

=495 kJ=495000J

1 mol = 6.022\times 10^{23} molecules

Energy required to break 1 molecule of oxygen molecule= E

= E=\frac{495000 J}{6.022\times 10^{23}}=8.219\times 10^{-19} J

The energy required to break the  1 molecule of oxygen is equal to enrgy of one photon of a sunlight.

E=\frac{h\times c}{\lambda}

where,

\lambda = wavelength of the light

E = energy of the photon

h = Planck's constant = 6.63\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda=\frac{h\times c}{E}

\lambda =\frac{6.63\times 10^{-34}Js \times 3\times 10^8m/s}{8.219\times 10^{-19} J}=2.42\times 10^{-7} m=242 nm

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

4 0
3 years ago
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