What is the name of this hydrocarbon? 2–methylpentyne 2–dimethylpentene 2,3–dimethylpentane 3,2–dimethylpentane
1 answer:
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CO₂ + H₂O -------> H₂CO₃
moles of CO₂ =
=
= 11.997 mol
mole ratio of CO₂ : H₂O = 1 : 1
∴ moles of H₂O = (`11.997 mol ) * 1
= 11.997 mol
≈ 12 mol
moles of CO₂ =
=
= 11.997 mol
mole ratio of CO₂ : H₂O = 1 : 1
∴ moles of H₂O = (`11.997 mol ) * 1
= 11.997 mol
≈ 12 mol
Answer:
The answer to your question is 15500 mg of MgSO₄ 7H₂O
Explanation:
Data
Volume = 30 ml
Concentration = 0.3 M
Formula MgSO4∗7H2O
Process
1.- Calculate the number of moles needed
Molarity = moles / volume
Solve for moles
moles = Molarity x volume
Substitution
moles = 0.3 x 0.03 l
moles = 0.009 moles of MgSO₄
2.- Calculate the molecular mass of MgSO4∗7H2O
molecular mass = 24 + 32 + 64 + 14 + 112
= 246 g
3.- Get the proportion MgSO4 :7H2O, this proportion is 1 : 7
4.- Calculate the amount of MgSO4∗7H2O
Simplification
15.5 g = 15500 mg