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anzhelika [568]
1 year ago
11

The _____ was a political protest against the british prohibition of yankee traders from dealing directly with merchants in cant

on.
Social Studies
1 answer:
Korvikt [17]1 year ago
3 0

The Boston Tea Party was a political protest against the British prohibition of Yankee traders from dealing directly with merchants in canton.

The Boston Tea Party was a political demonstration that took place at Griffin's Wharf in Boston, Massachusetts, on December 16, 1773. 342 chests of tea that had been imported by the British East India Company were dumped into the harbor by American colonists who were disgruntled and outraged with Britain for enforcing "taxation without representation."

Yankee traders were American businessmen and drug smugglers in the past, especially at the turn of the 19th century. The term "Yankee" was given to the traders since many of them were from Boston or other New England ports.

To learn more about political protest here: brainly.com/question/10503612

#SPJ4

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Hens usually begin laying eggs when they are about 6 months old. Young hens tend to lay smaller​ eggs, often weighing less than
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Answer:

          \large\boxed{\large\boxed{1.33g}}

Explanation:

Your question has one part only: <em>a) The average weight of the eggs produced by the young hens is 50.1 ​grams, and only 25​% of their eggs exceed the desired minimum weight. If a Normal model is​ appropriate, what would the standard deviation of the egg weights​ be?</em>

<em />

<h2><em>Solution</em></h2><h2><em /></h2>

You are given the <em>mean</em>, the reference value, and the <em>percent of egss that exceeds that minimum</em>.

In terms of the parameters of a normal distribution that is:

  • <em>mean</em> =<em> 50.1g</em> (μ)
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Using a standard<em> normal distribution</em> table, you can find the Z-score for which the area under the curve is greater than 25%, i.e. 0.25

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Thus, you must interpolate. Since, (0.2514 + 0.2483)/2  ≈ 0.25, your Z-score is in the middle.

That is, Z-score = (0.67 + 0.68)/2 = 0.675.

Now use the formula for Z-score and solve for the <em>standard deviation</em> (σ):

          Z-score=(x-\mu)/\sigma

          0.675=(51g-50.1g)/\sigma

          \sigma =0.9g/0.675=1.33g

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