Why do you think elements on the left side of the table would want to react with ones on the right side?
1 answer:
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Answer: No I+ cannot be called a Lewis base.
Explanation:
According to Lewis Theory, it defines an acid as an electron-pair acceptor and a base as an electron-pair donor.
In terms of Lewis basicity, Iodide ion (anions) has the more readily available lone pair electrons for donation since iodide ion is less electronegative .
With the help of the net electronic structure one can understand the answer of the question, because we need to study the I+ ion (cation) structure.
Lewis acid is therefore any substance, that can accept a pair of nonbonding electrons.
From the picture below I+ is most likely ready to accept electrons not to give from it 5s orbital to become stable.
The rate at which radioactive substances disintegrate is a constant for a
given radioactive material.
- <u>The fossil is 710 million years old</u>.
Reasons:
The half-life of a radioactive material is the time it takes half of the nucleus
of a radioactive material to disintegrate into other forms of materials
through the given off of energy and particles.
The half life of Uranium 235 = 710 million years
The product of the decay of Uranium 235 = Lead 207
The mass of Uranium 235 in the fossil = 4 micrograms
The mass of Lead 207 in the sample = 4 micrograms
Therefore, the mass of Lead 207 in the fossil is equal to the mass of
Uranium 235, therefore, a minimum of half of the Uranium 235 has
decomposed, which gives;
The time of decomposition of the Uranium 235 = 1 Half life = 710 million years
The age of the fossil = The time in which the Uranium has been
decomposing = The time of decomposition = 1 half life of Uranium 235 = 710
million years
- <u>The age of the fossil = 710 million years</u>
Using the formula for half-life, we get;
The fossil contains initially only Uranium 235 with a minimum mass of 4 mg
+ 4 mg = 8 mg, which gives;
N₀ = 8 mg
N(t) = The current mass of Uranium 235 = 4 mg
= 710 million years
Therefore;
t = 710
- <u>The age of the fossil, </u><u><em>t</em></u><u> = 710 million years</u>
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Answer:
Are produced 12,1 g of AlCl₃ and 5,33 g of Al₂O₃ are left over
Explanation:
For the reaction:
Al₂O₃ (s) + 6 HCl (aq) → 2AlCl₃ (aq) + 3H₂0(l)
10,0g of Al₂O₃ are:
10,0g ₓ = <em>0,0980 moles</em>
And 10,0g of HCl are:
10,0 gₓ = <em>0,274 moles</em>
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For a total reaction of 0,274 moles of HCl you need:
0,274× = <em>0,0457 moles of Al₂O₃</em>
Thus, limiting reactant is HCl
The grams produced of AlCl₃ are:
0,274 moles HCl × × 133
= <em>12,1 g of AlCl₃</em>
<em />
The moles of Al₂O₃ that don't react are:
0,0980 moles - 0,0457 moles =<em> </em>0,0523 moles
And its mass is:
0,0523 molesₓ = <em>5,33 g of Al₂O₃ </em>
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I hope it helps!