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photoshop1234 [79]
3 years ago
5

Naming compoundsdoes anyone know the answers for these or at least one of them ?​

Chemistry
2 answers:
Arada [10]3 years ago
6 0

Answer:

KNO3- Potassium Nitrate, KOH- Potassium hydroxide, K2CRO4- Potassium chromate

Explanation:

Vaselesa [24]3 years ago
3 0

Answer:

KNO3=Potassium, nitrogen, oxygen3

KOH= Potassium, oxygen, and hydrogen

K2CRO4=Potassium2, chromium, oxygen4

Compound names

KNO3= Potassium Nitrate

KOH= Potassium hydroxide

K2CrO4= Potassium chromate

Hope it helps

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Why chemically did the prescribing of thalidomide for morning sickness in pregnant women lead to tragic consequences, including
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Answer:

See explanation

Explanation:

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3 0
3 years ago
Consider the following reaction: 2CH3OH(g)  2CH4(g) + O2(g) ΔH = +252.8 kJ a) Calculate the amount of heat transferred when 24.
denpristay [2]

<u>Answer:</u>

<u>For a:</u> The amount of heat transferred for the given amount of methanol is 94.6736 kJ.

<u>For b:</u> The mass of methane gas produced will be 10.384 g.

<u>Explanation:</u>

For the given chemical reaction:

2CH_3OH(g)\rightarrow 2CH_4(g)+O_2(g);\Delta H=+252.8kJ

  • <u>For a:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of methanol = 24.0 g

Molar mass of methanol = 32.04 g/mol

Putting values in above equation, we get:

\text{Moles of methanol}=\frac{24.0g}{32.04g/mol}=0.749mol

By Stoichiometry of the reaction:

For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.

So, for every 0.749 moles of methanol, the amount of heat transferred will be = \frac{252.8}{2}\times 0.749=94.6736kJ

Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.

  • <u>For b:</u>

By Stoichiometry of the reaction:

252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.

So, 82.1 kJ of energy will be absorbed when = \frac{2}{252.8}\times 82.1=0.649mol of methane gas is produced.

Now, calculating the mass of methane gas from equation 1, we get:

Molar mass of methane gas = 16 g/mol

Moles of methane gas = 0.649 moles

Putting values in equation 1, we get:

0.649mol=\frac{\text{Mass of methane gas}}{16g/mol}\\\\\text{Mass of methane}=10.384g

Hence, the mass of methane gas produced will be 10.384 g.

7 0
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Why does hydrogen fluoride have a high boiling point
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3 0
2 years ago
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