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photoshop1234 [79]
3 years ago
5

Naming compoundsdoes anyone know the answers for these or at least one of them ?​

Chemistry
2 answers:
Arada [10]3 years ago
6 0

Answer:

KNO3- Potassium Nitrate, KOH- Potassium hydroxide, K2CRO4- Potassium chromate

Explanation:

Vaselesa [24]3 years ago
3 0

Answer:

KNO3=Potassium, nitrogen, oxygen3

KOH= Potassium, oxygen, and hydrogen

K2CRO4=Potassium2, chromium, oxygen4

Compound names

KNO3= Potassium Nitrate

KOH= Potassium hydroxide

K2CrO4= Potassium chromate

Hope it helps

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You must add 75 mL water to 195 mL 90 % alcohol to make 270 mL of 65 % alcohol.

<em>Step 1.</em> Calculate the volume of 90 % alcohol needed

You can use the dilution formula

<em>V</em>1×<em>C</em>1 = <em>V</em>2×<em>C</em>2

where

<em>V</em>1 and<em> V</em>2 are the volumes of the two solutions

<em>C</em>1 and <em>C</em>2 are the concentrations

You can solve the above formula to get

<em>V</em>2 = <em>V</em>1 × <em>C</em>1/<em>C</em>2

<em>V</em>1 = 270 mL; <em>C</em>1 = 65 %

V2 = ?; _____<em>C</em>2 = 90 %

∴<em>V</em>2 = 270 mL × (65 %/90 %) = 195 mL

You need 195 mL of 90 % alcohol to make 270 mL of 65 % RA

<em>Step 2</em>. Calculate the amount of water to add.

Volume of water = 270 mL – 195 mL = 75 mL

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3 years ago
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