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navik [9.2K]
3 years ago
14

Can I+ (the iodine cation) becalled a Lewis base? Fullyexlplain your answer.

Chemistry
1 answer:
Alenkinab [10]3 years ago
7 0

Answer: No I+ cannot be called a Lewis base.

Explanation:

According to Lewis Theory, it defines an acid as an electron-pair acceptor and a base as an electron-pair donor.

In terms of Lewis basicity, Iodide ion (anions) has the more readily available lone pair electrons for donation since iodide ion is less electronegative .

With the help of the net electronic structure one can understand the answer of the question, because we need to study the I+  ion (cation) structure.

Lewis acid is therefore any substance, that can accept a pair of nonbonding electrons. 

From the picture below I+ is most likely ready to accept electrons not to give from it 5s orbital to become stable.

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What mass of hydrogen contains the same number of atoms as 7.00 g of nitrogen
Leto [7]
Molecular mass of nitrogen, N2 = 2*14 = 28
molecular mass of hydrogen, H2=2*1 = 2

Molecules of both elements contain 2 atoms, so the ratio of molecules is the same as the ratio of atoms.

From the molecular masses above, 
ratio of number of molecules = ratio of molecular masses, therefore
7g N2 : x g H2 = 28:2
cross multiply:
x=7*2/28=0.5 g of Hydrogen has the same number of atoms as 7 g of nitrogen (at room temperatures)

7 0
3 years ago
How many moles of Mg(OH)2 will react with 2.5 mol HCI?
bekas [8.4K]

Answer:

1.25mole of Mg(OH)₂

Explanation:

The reaction is between Mg(OH)₂ and HCl, this is a neutralization reaction between an acid and a base.

         Mg(OH)₂   +   2HCl   →   MgCl₂   + 2H₂O

The balanced reaction equation is given above.

           2 mole of HCl reacts with 1 mole of Mg(OH)₂

So,       2.5mole of HCl will react with \frac{2.5}{2}  = 1.25mole of Mg(OH)₂

The number of moles of Mg(OH)₂ is given as 1.25mol

5 0
3 years ago
HELP!!!!<br> please omg
OverLord2011 [107]

Answer:

I believe it's A. to reduce air bubbles. Tbh, it's been a while

7 0
3 years ago
The reducing agent in this catalytic hydrogenation reaction was molecular hydrogen (H2), which was produced in situ (in the reac
creativ13 [48]

Answer:

a)  After the balloon inflated after 440 uL of dropwise due to the reaction of 1-Decene and the solution in the conical vial. b) 4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7} c) No H_{2} was not the limiting reactant.

Explanation:

Generally, hydrogenation is the chemical reaction between a compound or element and molecular hydrogen in the presence of catalysts such as platinum.

a) After the balloon inflated after 440 uL of dropwise 1-Decene solution was added due to the reaction between 1-Decene and the solution in the conical vial.

b)  4NaBH_{4} + 2HCl + 7H_{2}O ⇒ 16H_{2(g)}+ 2NaCl + Na_{2}B_{4}O_{7}

c) H_{2} was not the limiting reactant based on the mol to mol ratio of H_{2} and decane which is 1:1. Therefore, if 0.8 mol of decane was produced then 0.8 mol of H_{2} would also be produced.

4 0
3 years ago
a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
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