1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
navik [9.2K]
3 years ago
14

Can I+ (the iodine cation) becalled a Lewis base? Fullyexlplain your answer.

Chemistry
1 answer:
Alenkinab [10]3 years ago
7 0

Answer: No I+ cannot be called a Lewis base.

Explanation:

According to Lewis Theory, it defines an acid as an electron-pair acceptor and a base as an electron-pair donor.

In terms of Lewis basicity, Iodide ion (anions) has the more readily available lone pair electrons for donation since iodide ion is less electronegative .

With the help of the net electronic structure one can understand the answer of the question, because we need to study the I+  ion (cation) structure.

Lewis acid is therefore any substance, that can accept a pair of nonbonding electrons. 

From the picture below I+ is most likely ready to accept electrons not to give from it 5s orbital to become stable.

You might be interested in
When a scientific investigation runs for several years, which is most likely true?
Bingel [31]

Answer:

1. Many different hypotheses will be tested.

Explanation:

Scientists test every hypothesis they make for their investigation, before moving onto bigger conclusions.

4 0
4 years ago
Read 2 more answers
A balloon contains 11.1 g of nitrogen monoxide gas (NO). how many molecules are in the balloon?
grandymaker [24]

The number of molecules that are in balloon are = 2.227 x10^23 molecules

<h3> calculation</h3>

calculate the number of moles of NO

moles = mass/molar mass

molar mass  of NO = 14+ 16 = 30 g/mol

moles is therefore=  11.1 g/30g/mol= 0.37 moles

by use of Avogadro's constant that is

                                     1 mole= 6.02 x10^23  molecules

                                          0.37 =? molecules

=(6.02 x10^23 x  0.37 moles)/ 1mole=2.227 x10^23 molecules

4 0
3 years ago
According to ___, if you decrease the volume of a container of gas and hold the temperature constant, the pressure of the gas wi
Savatey [412]
Charles law is right answer
7 0
4 years ago
Read 2 more answers
The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically. The following data was obtained: t/min 0
o-na [289]

Answer:

1) The order of the reaction is of FIRST ORDER

2)   Rate constant k = 5.667 × 10 ⁻⁴

Explanation:

From the given information:

The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically.

liquid-phase reaction 2A - B signifies that the reaction is of FIRST ORDER where the rate of this reaction is directly proportional to the concentration of A.

The following data was obtained:

t/min                    0         10         20          30             40          ∞

conc B/(mol/L)    0       0.089    0.153     0.200       0.230    0.312

For  a first order reaction:

K = \dfrac{1}{t} \ In ( \dfrac{C_{\infty} - C_o}{C_{\infty} - C_t})

where :

K = proportionality  constant or the rate constant for the specific reaction rate

t = time of reaction

C_o = initial concentration at time t

C _{\infty} = final concentration at time t

C_t = concentration at time t

To start with the value of t when t = 10 mins

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 - 0}{0.312 - 0.089})

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 }{0.223})

K_1 =0.03358 \  min^{-1}

K_1 \simeq 0.034 \  min^{-1}

When t = 20

K_2= \dfrac{1}{20} \ In ( \dfrac{0.312 - 0}{0.312 - 0.153})

K_2= 0.05 \times  \ In ( 1.9623)

K_2=0.03371 \ min^{-1}

K_2 \simeq 0.034 \ min^{-1}

When t = 30

K_3= \dfrac{1}{30} \ In ( \dfrac{0.312 - 0}{0.312 - 0.200})

K_3= 0.0333 \times  \ In ( \dfrac{0.312}{0.112})

K_3= 0.0333 \times  \ 1.0245

K_3 = 0.03412 \ min^{-1}

K_3 = 0.034 \ min^{-1}

When t = 40

K_4= \dfrac{1}{40} \ In ( \dfrac{0.312 - 0}{0.312 - 0.230})

K_4=0.025 \times  \ In ( \dfrac{0.312}{0.082})

K_4=0.025 \times  \ In ( 3.8048)

K_4=0.03340 \ min^{-1}

We can see that at the different time rates, the rate constant of k_1, k_2, k_3, and k_4 all have similar constant values

As such :

Rate constant k = 0.034 min⁻¹

Converting it to seconds ; we have :

60 seconds = 1 min

∴

0.034 min⁻¹ =(0.034/60) seconds

= 5.667 × 10 ⁻⁴ seconds

Rate constant k = 5.667 × 10 ⁻⁴

4 0
3 years ago
Calculate the pH of a solution that has a [OH−] of 2.6 × 10^−6 M.
TiliK225 [7]

Answer:

A. 8.4

Explanation:

[OH⁻] = 2.6 × 10⁻⁶               Take the negative log of each side

-log[OH⁻] = pOH = 5.59     Apply the pH/pOH relation

pH + pOH = 14.00               Insert the value of pOH

pH + 5.59 = 14.00               Subtract 5.59 from each side

pH = 14.00 -5.59 = 8.41

7 0
3 years ago
Other questions:
  • Suppose you have 0.100 m3 of co2, at pressure of 2.00 atm, and a temperature of 30.0?c. How many grams of co2 do you have? Expre
    6·1 answer
  • Which of the following are examples of physical change? Copper oxidizing Iron rusting Carbon dioxide sublimating Water evaporati
    8·1 answer
  • Which is a type of protein?
    12·2 answers
  • Luciana explains to Eric how electricity flows in a circuit. Which sentences are a part of her explanation? Select all that appl
    5·2 answers
  • Darwin found that genetic drift was most likely to have an effect on variation in __________.
    14·2 answers
  • PLeas hurry
    12·2 answers
  • Determine the energy associated with an e- in hydrogen at n=1 and also at n=t?
    11·1 answer
  • PLESE HELP WILL GIVE BRAINLYESTY
    13·1 answer
  • Convection currents in Earth's core transfer heat and material to the surface.
    7·1 answer
  • Help me pLSSSSSSSSSSSSSSS​
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!