Answer : The mass of
formed will be, 468.18 grams.
Solution : Given,
Mass of Al = 124 g
Mass of
= 601 g
Molar mass of Al = 27 g/mole
Molar mass of
= 160 g/mole
Molar mass of
= 102 g/mole
First we have to calculate the moles of Al and
.
![\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{124g}{27g/mole}=4.59moles](https://tex.z-dn.net/?f=%5Ctext%7B%20Moles%20of%20%7DAl%3D%5Cfrac%7B%5Ctext%7B%20Mass%20of%20%7DAl%7D%7B%5Ctext%7B%20Molar%20mass%20of%20%7DAl%7D%3D%5Cfrac%7B124g%7D%7B27g%2Fmole%7D%3D4.59moles)
![\text{ Moles of }Fe_2O_3=\frac{\text{ Mass of }Fe_2O_3}{\text{ Molar mass of }Fe_2O_3}=\frac{601g}{160g/mole}=3.76moles](https://tex.z-dn.net/?f=%5Ctext%7B%20Moles%20of%20%7DFe_2O_3%3D%5Cfrac%7B%5Ctext%7B%20Mass%20of%20%7DFe_2O_3%7D%7B%5Ctext%7B%20Molar%20mass%20of%20%7DFe_2O_3%7D%3D%5Cfrac%7B601g%7D%7B160g%2Fmole%7D%3D3.76moles)
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
![2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe](https://tex.z-dn.net/?f=2Al%2BFe_2O_3%5Crightarrow%20Al_2O_3%2B2Fe)
From the balanced reaction we conclude that
As, 2 mole of
react with 1 mole of ![Fe_2O_3](https://tex.z-dn.net/?f=Fe_2O_3)
So, 4.59 moles of
react with
moles of ![Fe_2O_3](https://tex.z-dn.net/?f=Fe_2O_3)
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of ![Al_2O_3](https://tex.z-dn.net/?f=Al_2O_3)
From the reaction, we conclude that
As, 2 mole of
react to give 2 mole of ![Al_2O_3](https://tex.z-dn.net/?f=Al_2O_3)
So, 4.59 moles of
react to give
moles of ![Al_2O_3](https://tex.z-dn.net/?f=Al_2O_3)
Now we have to calculate the mass of ![Al_2O_3](https://tex.z-dn.net/?f=Al_2O_3)
![\text{ Mass of }Al_2O_3=\text{ Moles of }Al_2O_3\times \text{ Molar mass of }Al_2O_3](https://tex.z-dn.net/?f=%5Ctext%7B%20Mass%20of%20%7DAl_2O_3%3D%5Ctext%7B%20Moles%20of%20%7DAl_2O_3%5Ctimes%20%5Ctext%7B%20Molar%20mass%20of%20%7DAl_2O_3)
![\text{ Mass of }Al_2O_3=(4.59moles)\times (102g/mole)=468.18g](https://tex.z-dn.net/?f=%5Ctext%7B%20Mass%20of%20%7DAl_2O_3%3D%284.59moles%29%5Ctimes%20%28102g%2Fmole%29%3D468.18g)
Therefore, the mass of
formed will be, 468.18 grams.