Solve the following system of equations using the elimination method. 5x – 5y = 10 6x – 4y = 4

Mathematics

1 answer:

tresset_1 [31]3 years ago

8 0

Answer:

x=-2,y=-4

Step-by-step explanation:

By dividing to lowest terms

5x – 5y = 10= x-y=2.......(1)

6x – 4y = 4=3x-2y=2........(2)

By elimination method

Multiply equation (1) by 3 so as to correspond with equation (2)

3(x-y)=3(2)

3x-3y=6..........(3)

Multiply equation (2) by 1 so as to correspond with equation (1)

1(3x-2y)=1(2)

3x-2y=2..........(4)

Then equation (3)-equation (4)

(3x-3y=6)

(3x-2y=2)

__________

-y=4

y=-4

Substitute y=-4 into equation(1)

x-(-4)=2

x+4=2

x=-2

Therefore x=-2,y=-4

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dimaraw [331]

Answer:

Step-by-step explanation:

$\int 3x(x^2+3)^4 \ dx$ .

It is apparently obvious we could expand the bracket and integrate term-by-term. This method would work but is very time consuming (and you could easily make a mistake) so we use a different method: integration by substitution.

Integration by substitution involves swapping the variable $x$ for another variable which depends on x: $u(x)$ . (We are going to choose $u$ for this question).

The very first step is to choose a suitable substitution. That is, an equation $u=f(x)$ which is going to make the integration easier. There is a trick for spotting this however: if an integral contains both a term and it's derivative then use the substitution $u=\text{The Term}$ .

Your integral contains the term $x^2 + 3$ . The derivative is $2x$ and (ignoring the constants) we see $x$ is also in the integral and so the substitution $u=x^2+3$ will unravel this integral!

Step 2: We must now swap the variable of integration from x to u. That means interchanging all the x's in the integrand (the term being integrated) for u's and also swapping (dx" to "du").

$u=x^2+3 \Rightarrow \frac{du}{dx}=2x \Rightarrow dx = \frac{1}{2x} du$