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Scorpion4ik [409]
1 year ago
5

Write the slope-intercept form of the equation of the line described.4) through: (-5,0) , parallel to Y= -2/5x + 4

Mathematics
1 answer:
elixir [45]1 year ago
8 0

To write the slope form quation

First; find the slope of

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The first two angles in a triangle are 90 degrees and 50 degrees. What does the third angle have to be?
s2008m [1.1K]

Answer:

B) 40 degrees

Step-by-step explanation:

90 + 50 = 140

Each triangle have 180 °

180 - 140 = 40

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3 years ago
Yana and Amber play a word game using tile letters. Each person takes 7 tiles from a set of tiles. Points are earned by using th
aleksley [76]

Answer:

A Yana's average number of points is 0.5 points greater than Amber's

Step-by-step explanation:

i added up all of Yana's points = 15

I added up all of Amber's points = 12

then i divided them both by 6 because there is 6 numbers total so then i got

Yana = 2.5 Amber = 2


2.5 - 2 = 0.5 so Yana's average number of points is 0.5 points greater than Amber's

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8 0
3 years ago
Help before 10:05 Please
julsineya [31]
1: 3 and 2/5
2: 8 and 1/2
3: 2 and 13/20
4: 2 and 4/5
5: 3 and 9/10
6: 8 and 4/5
7: 3 and 92/100
3 and 46/50
8: 6 and 69/100
9: 6 and 7:50
10: 9 and 1/10
11: 10 and 11/100
12: 7 and 1/5
13: 10 and 23/100
14: 5 and 1/5
3 0
3 years ago
Read 2 more answers
What is the difference between bernoulii equation and riccati equation
melisa1 [442]
The Bernoulli equation is almost identical to the standard linear ODE.

y'=P(x)y+Q(x)y^n

Compare to the basic linear ODE,

y'=P(x)y+Q(x)

Meanwhile, the Riccati equation takes the form

y'=P(x)+Q(x)y+R(x)y^2

which in special cases is of Bernoulli type if P(x)=0, and linear if R(x)=0. But in general each type takes a different method to solve. From now on, I'll abbreviate the coefficient functions as P,Q,R for brevity.

For Bernoulli equations, the standard approach is to write

y'=Py+Qy^n
y^{-n}y'=Py^{1-n}+Q

and substitute v=y^{1-n}. This makes v'=(1-n)y^{-n}y', so the ODE is rewritten as

\dfrac1{1-n}v'=Pv+Q

and the equation is now linear in v.

The Riccati equation, on the other hand, requires a different substitution. Set v=Ry, so that v'=R'y+Ry'=R'\dfrac vR+Ry'. Then you have

y'=P+Qy+Ry^2
\dfrac{v'-R'\dfrac vR}R=P+Q\dfrac vR+R\dfrac{v^2}{R^2}
v'=PR+\left(Q+\dfrac{R'}R\right)v+v^2

Next, setting v=\dfrac{u'}u, so that v'=\dfrac{uu''-(u')^2}{u^2}, allows you to write this as a linear second-order equation. You have

\dfrac{uu''-(u')^2}{u^2}=PR+\left(Q+\dfrac{R'}R\right)\dfrac{u'}u+\dfrac{(u')^2}{u^2}
u''-\left(Q+\dfrac{R'}R\right)u'+PRu=0
u''+Su'+Tu=0

where S=-\left(Q+\dfrac{R'}R\right) and T=PR.
3 0
3 years ago
What is the lateral area of the Triangular Prism?
Anuta_ua [19.1K]

Answer:

D)210 units ^2 I hope the answer is correct. I will be happy when I get 10 points

6 0
2 years ago
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