Answer:
The volume is ![V=\frac{64}{15}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B64%7D%7B15%7D)
Step-by-step explanation:
The General Slicing Method is given by
<em>Suppose a solid object extends from x = a to x = b and the cross section of the solid perpendicular to the x-axis has an area given by a function A that is integrable on [a, b]. The volume of the solid is</em>
![V=\int\limits^b_a {A(x)} \, dx](https://tex.z-dn.net/?f=V%3D%5Cint%5Climits%5Eb_a%20%7BA%28x%29%7D%20%5C%2C%20dx)
Because a typical cross section perpendicular to the x-axis is a square disk (according with the graph below), the area of a cross section is
The key observation is that the width is the distance between the upper bounding curve
and the lower bounding curve ![y = x^2](https://tex.z-dn.net/?f=y%20%3D%20x%5E2)
The width of each square is given by
![w=(2-x^2)-x^2=2-2x^2](https://tex.z-dn.net/?f=w%3D%282-x%5E2%29-x%5E2%3D2-2x%5E2)
This means that the area of the square cross section at the point x is
![A(x)=(2-2x^2)^2](https://tex.z-dn.net/?f=A%28x%29%3D%282-2x%5E2%29%5E2)
The intersection points of the two bounding curves satisfy
, which has solutions x = ±1.
![2-x^2=x^2\\-2x^2=-2\\\frac{-2x^2}{-2}=\frac{-2}{-2}\\x^2=1\\\\x=\sqrt{1},\:x=-\sqrt{1}](https://tex.z-dn.net/?f=2-x%5E2%3Dx%5E2%5C%5C-2x%5E2%3D-2%5C%5C%5Cfrac%7B-2x%5E2%7D%7B-2%7D%3D%5Cfrac%7B-2%7D%7B-2%7D%5C%5Cx%5E2%3D1%5C%5C%5C%5Cx%3D%5Csqrt%7B1%7D%2C%5C%3Ax%3D-%5Csqrt%7B1%7D)
Therefore, the cross sections lie between x = -1 and x = 1. Integrating the cross-sectional areas, the volume of the solid is
![V=\int\limits^{1}_{-1} {(2-2x^2)^2} \, dx\\\\V=\int _{-1}^14-8x^2+4x^4dx\\\\V=\int _{-1}^14dx-\int _{-1}^18x^2dx+\int _{-1}^14x^4dx\\\\V=\left[4x\right]^1_{-1}-8\left[\frac{x^3}{3}\right]^1_{-1}+4\left[\frac{x^5}{5}\right]^1_{-1}\\\\V=8-\frac{16}{3}+\frac{8}{5}\\\\V=\frac{64}{15}](https://tex.z-dn.net/?f=V%3D%5Cint%5Climits%5E%7B1%7D_%7B-1%7D%20%7B%282-2x%5E2%29%5E2%7D%20%5C%2C%20dx%5C%5C%5C%5CV%3D%5Cint%20_%7B-1%7D%5E14-8x%5E2%2B4x%5E4dx%5C%5C%5C%5CV%3D%5Cint%20_%7B-1%7D%5E14dx-%5Cint%20_%7B-1%7D%5E18x%5E2dx%2B%5Cint%20_%7B-1%7D%5E14x%5E4dx%5C%5C%5C%5CV%3D%5Cleft%5B4x%5Cright%5D%5E1_%7B-1%7D-8%5Cleft%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5Cright%5D%5E1_%7B-1%7D%2B4%5Cleft%5B%5Cfrac%7Bx%5E5%7D%7B5%7D%5Cright%5D%5E1_%7B-1%7D%5C%5C%5C%5CV%3D8-%5Cfrac%7B16%7D%7B3%7D%2B%5Cfrac%7B8%7D%7B5%7D%5C%5C%5C%5CV%3D%5Cfrac%7B64%7D%7B15%7D)
For a relation to be function, every x value should have its unique image in co-domain. If x is related to more than one y value, then that relation is not a function
In 1, as you can see, 1 related to -7 as well as 8. Which means 1 has two images viz. -7 and 8. But for a relation to be function, x should have only one image. Thus, it is not a function.
The worst is the 4th one in which -2 has 4 images.
Therefore, only relation B is a function.
Answer:
I think b
Step-by-step explanation:
Step-by-step explanation:
756 = 2² * 3³ * 7.
For 756n to be a perfect cube, all of its prime factors must have a power that is a multiple of 3.
How to get from 2² to 2³: Multiply by 2.
3³ has already a power that is a multiple of 3.
How to get from 7 to 7³: Multiply by 7².
Hence n = 2 * 7² = 98.
Answer:
7/4 inches
Step-by-step explanation:
Longest bean sprout = 8/8 + 8/8
Longest bean sprout = 1 + 1
Longest bean sprout = 2
Shortest bean sprout = 2/8
Difference = 2 - 2/8
Difference = (16-2)/8
Difference = 14/8
Difference = 7/4
Hence the distance is 7/4 inches