Use the number line to find the coordinate of the midpoint of <br> ¯¯¯¯¯<br> J<br> P<br> .

What is the missing angle in the right triangle?

Ainat [17]

Answer:

68

Step-by-step explanation:

For angle A, 3 is the adjacent leg. 8 is the hypotenuse.

The trig ratio that relates the adjacent leg to the hypotenuse is the cosine.

$\cos A = \dfrac{adj}{hyp}$

$\cos A = \dfrac{3}{8}$

$\cos A = 0.375$

We know the cosine of angle A equals 0.375. We take the inverse cosine of 0.375 to find the measure of the angle.

$A = \cos^{-1} 0.375$

$A = 68^\circ$

8 0

3 years ago

The sum of two numbers is 67. the smaller number is 3 less than the larger number. what are the two numbers?

V125BC [204]

Let the larger number be x
The smaller number would be x-3

(x-3)+x=67
2x-3=67
2x=67-3
2x=64
x=64/2
x=32

Therefore the larger number is 32 and the smaller is (32)-3= 29

Hope I helped :)

7 0

3 years ago

Cuales son las fuentes primarias

Tamiku [17]

Answer:

Testigos de primera mano

6 0

3 years ago

Read 2 more answers

Starting at 6 a.m. every morning, Matilda receives text messages on her cell phone from her mother, her best friend, and her bro

Dafna1 [17]

Answer:

a) 0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

b) $1.6 \times 10^{-9}$ probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

A) Find the probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

Two from the best friend:

Her best friend sends a message once every 10 minutes.

From 6 to 7:30, there is an hour and a half, that is, 90 minutes, so the mean for her best friend is $\mu = \frac{90}{10} = 9$

Two messages is P(X = 2). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-9}*9^{2}}{(2)!} = 0.0050$

Two from the mother:

Message every hour = 60 minutes. So $\mu = \frac{90}{60} = 1.5$ . This is P(X = 2).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-1.5}*1.5^{2}}{(2)!} = 0.2510$

Two of her best friend and two of her mother:

Independent events, so the probability of both happening is the multiplication of their separate probabilities.

$p = 0.005*0.251 = 0.0013$

0.0013 = 0.13% probability that by 7:30 a.m. Mary receives exactly four messages – two of her best friend and two of her mother.

B) With a chance of 75% a text message contains a typo independent of the sender. Find the probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

In 3 hours, she is expected to receive:

3*60/10 = 18 messages from her best friend.

3*60/60 = 3 messages from her mother.

3*60/30 = 6 messages from her brother.

In total, 27 messages.

75% probability of a typo, so $\mu = 0.75*27 = 20.25$

This is P(X = 0).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20.25}*20.25^{0}}{(0)!} = 1.6 \times 10^{-9}$

$1.6 \times 10^{-9}$ probability that there are no typos in the text messages Matilda receives between 2 p.m. and 5 p.m.

8 0

3 years ago

eight members of a chess club are having a tournament. in the first round every player will play a chess game against every othe

Vlad1618 [11]

There will be 4 games in the first round because 8 members divided by 2 players per games equals 4 games. I hope that was what you were asking? If not let me know

5 0

3 years ago

Use the number line to find the coordinate of the midpoint of ¯¯¯¯¯ J P .