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user100 [1]
3 years ago
8

50 people took a rest before the test they predicted whether they would pass or fail 30 People predicted they would pass 26 of t

hose people who predicted they would pass it costs 37 people passed altogether complete the frequency tree
Mathematics
1 answer:
Gre4nikov [31]3 years ago
5 0
37-26=11
26+4+11=41
50-41=9
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Q= 4+0.8p what value of p would make the equation true if q was 70
just olya [345]

Answer:

82.5 = p

Step-by-step explanation:

Q= 4+0.8p

Let q = 70

70= 4+0.8p

Subtract 4 from each side

70-4= 4-4+0.8p

66 = .8p

Divide each side by .8

66/.8 = .8p/.8

82.5 = p

7 0
3 years ago
Player B’s longest home run distance is 500 ft. There are 5280 ft in 1 mi. How many home runs would Player B need to hit at his
Flura [38]
5280 ÷ 500 = (number of home runs needed to reach a mile distance)

5280 ÷ 500 = 10.56

cant hit part of a home run so round up to 11.
3 0
3 years ago
After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only three women among the last
mixer [17]

Answer:

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

Step-by-step explanation:

For each employee hired, the are only two possible outcomes. Either it is a man, or it is a woman. The probability of a person hired being a man or a woman is independent of any other person. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

21 new employees.

This means that n = 21

She also learns that the pool of applicants is very large, with an approximately equal number of qualified men as qualified women.

This means that p = 0.5

Help her address the charge of gender discrimination by finding the probability of getting three or fewer women when 21 people are hired.

This is

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{21,0}.(0.5)^{0}.(0.5)^{21} \approx 0

P(X = 1) = C_{21,1}.(0.5)^{1}.(0.5)^{20} = 0.00001

P(X = 2) = C_{21,2}.(0.5)^{2}.(0.5)^{19} = 0.0001

P(X = 3) = C_{21,3}.(0.5)^{3}.(0.5)^{18} = 0.0006

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.00001 + 0.0001 + 0.0006 = 0.00071

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

8 0
3 years ago
If -3 1/4 is subtracted from 1 1/3. What will be the result?
Alenkinab [10]

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-3_1/4 = -13/4

(4/3) - (-13/4)

(4/3) + (13/4)

We can see that (4/3) + (13/4) leads to a positive answer.

Answer: choice D

4 0
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7 0
3 years ago
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