The partial factorization of x2 – 3x – 10 is modeled with algebra tiles. Which unit tiles are needed to complete the factorizati
on? 2 negative unit tiles 2 positive unit tiles 5 negative unit tiles 5 positive unit tiles
2 answers:
X² - 3x - 10
x² = x * x
10 can be factored:
1 x 10 ⇒⇒⇒ difference between factors = 9
2 x 5 ⇒⇒⇒ difference between factors = 3 ⇒ (The correct pair)
(x-5)(x+2) = x(x+2) - 5(x+2)
= x² + 2x - 5x - 10
= x² - 3x - 10
∴ x - 5 = 0 ⇒⇒⇒ x = 5
x + 2 = 0 ⇒⇒⇒ x = -2
I have attached <span>algebra tiles for the given equation.</span>
x² = x * x
10 can be factored:
1 x 10 ⇒⇒⇒ difference between factors = 9
2 x 5 ⇒⇒⇒ difference between factors = 3 ⇒ (The correct pair)
(x-5)(x+2) = x(x+2) - 5(x+2)
= x² + 2x - 5x - 10
= x² - 3x - 10
∴ x - 5 = 0 ⇒⇒⇒ x = 5
x + 2 = 0 ⇒⇒⇒ x = -2
I have attached <span>algebra tiles for the given equation.</span>
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Question:
James has 14,500g of sand in his sandbox. He brings home another 7,400g of sand from the beach to add to his sandbox. How many kilograms of sand does James have in his sandbox now?
Answer:
The quantity of sandbox James has is 21.9kg
Step-by-step explanation:
Given
Initial quantity of sandbox = 14,500 g
Additional quantity = 7,400 g
Required
Total quantity of sandbox in kg
Tp get the total quantity of sandbox, we simply add in the initial and additional quantity of sandbox together;
This is represented mathematically as follows;
Total = Initial Quantity + Additional Quantity
Total = 14,500 g + 7,400 g
Total = 21,900 g
But the question says the answer should be in kg
1000 g is equivalent to 1 kg
21,900 g will be equivalent to
Hence, the quantity of sandbox James has is 21.9kg
Answer:
565.49 or if rounded to the nearest tenth, 565.5
Explanation:
The formula for finding the volume of a cone is V=1/3Bh
B = pi times the radius squared
h = height
Substitute 6 for r and 15 for h.
V= 1/3··(
)·15
Multiply.
V= 565.49 or 565.5 rounded to the nearest tenth.