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Alina [70]
2 years ago
15

Read the following statement.

Physics
1 answer:
Sergio039 [100]2 years ago
5 0

The statement  "the knowledge produced by science builds on old ideas and is constantly changing" is absolutely agreeable.

We can see the above statement repeating itself in various situations and has led to the discovery of new laws which are now used in all areas of science. The best example of the above statement is The universal gas law, PV = nRT, which is the combination of two laws, Boyle's law, Charle's Law and Avogadro's Law.

According to Boyle's Law, gas volume grows as pressure lowers.

Charles' Law states that the gas expands in volume as its temperature rises.

As per Avogadro's Law, that as the gas concentration rises, so does its volume.

To know more about universal gas law, refer here

brainly.com/question/24519415

#SPJ4

You might be interested in
Answer the following question according to formal grammatical rules.
VARVARA [1.3K]

Answer:

c

Explanation:

just trying to follow basic grammar.

5 0
3 years ago
What is the emf of this cell under standard conditions? Express your answer using three significant figures.
madreJ [45]

Complete Question

A voltaic cell utilizes the following reaction and operates at 298 K:

3Ce4+(aq)+Cr(s)→3Ce3+(aq)+Cr3+(aq).

What is the emf of this cell under standard conditions? Express your answer using three significant figures.

Answer:

The value is E^o_{cell}  = 2.35 V

Explanation:

From the question we are told that

   The ionic equation is  

               3 Ce^{4 +}  _{(aq)}  +  Cr _{(s)}  \to  3 Ce^{3+} _{(aq)}  +  Cr^{3r}  _{(aq)}

Now under standard conditions the reduction  half reaction  is

      Ce^{4+}  + e \to Ce^{3+}  ; \ \ E^o_r  =  1.61 V

And the oxidation half reaction is

      Cr^{3+}  +  3e^{-}  \to  Cr ; \    \  \  E^o_o  =  - 0.74 V

The emf of this cell under standard conditions  is mathematically represented as

     E^o_{cell}  =  E^o _r -  E^o _o

substituting values

     E^o_{cell}  =  1.61  - (- 0.74)

    E^o_{cell}  = 2.35 V

     

3 0
3 years ago
A series RCL circuit consists of a 50 Ω resistor, 500 Ω capacitor, and a 500 Ω inductor. What is the angle of impedance?
lbvjy [14]

Answer:

Zero

Explanation:

here, the inductive reactance and the capacitive reactance is same, so this is the condition for resonance.

In the condition for resonance,

the circuit and the voltage in the circuit is in the same phase and the impedance of the circuit is minimum which is equal to the resistance of the circuit.

The phase angle is given by

tan\phi =\frac{X_{L}-X_{C}}{R}

Ф = 0

5 0
3 years ago
Suppose a piano tuner stretches a steel piano wire 7.5 mm. The wire was originally 0.975 mm in diameter, 1.45 m long, and has a
Tasya [4]

The forces a piano tuner applies to stretch the steel piano wire willl be 1.4 × 10¹¹ N.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.

The application of a force may be used to describe the steel as an elastic element within a certain range of applied force.

Given data;

Young modulus, E=2.10 × 10¹¹ N/m²

Cross-sectional area,A

Final length,\rm L_f = 1.45 m = 1450 \ mm

Initial length,\rm L_i = 7.5 mm

\rm F  = \frac{(L_f-L_i)(E)(A)}{L_1} \\\\ \rm F  = \frac{(1450 - 7.5)(2.0 \times 0^{11})(0.746)}{1450} \\\\ F = 1.4 \times 10^{11} \ N

Hence, the force a piano tuner applies to stretch the steel piano wire willl be 1.4 × 10¹¹ N.

To learn more about the force refer to the link;

brainly.com/question/26115859

#SPJ1

8 0
2 years ago
A brick lands 10.1 m from the base of a building. If it was given an initial velocity of 8.6 m/s [61º above the horizontal], how
Montano1993 [528]
<h2>Answer: 10.52m</h2><h2 />

First, we have to establish the <u>reference system</u>. Let's assume that the building is on the negative y-axis and that the brick was thrown at the origin (see figure attached).

According to this, the initial velocity V_{o} has two components, because the brick was thrown at an angle \alpha=61\º:

V_{ox}=V_{o}cos\alpha   (1)

V_{ox}=8.6\frac{m}{s}cos(61\º)=4.169\frac{m}{s}  (2)

V_{oy}=V_{o}sin\alpha   (3)

V_{oy}=8.6\frac{m}{s}sin(61\º)=7.521\frac{m}{s}   (4)

As this is a projectile motion, we have two principal equations related:

<h2>In the x-axis: </h2>

X=V_{ox}.t  (5)

Where:

X=10.1m is the distance where the brick landed

t is the time in seconds

If we already know X and V_{ox}, we have to find the time (we will need it for the following equation):

t= \frac{X}{ V_{ox}}  (6)

t=2.42s  (7)

<h2>In the y-axis: </h2>

-y=V_{oy}.t+\frac{1}{2}g.t^{2}   (8)

Where:

y is the height of the building (<u>in this case it has a negative sign because of the reference system we chose)</u>

g=-9.8\frac{m}{s^{2}} is the acceleration due gravity

Substituting the known values, including the time we found on equation (7) in equation (8), we will find the height of the building:

-y=(7.521\frac{m}{s})(2.42s)+\frac{1}{2}(-9.8\frac{m}{s^{2}}).(2.42s)^{2}   (9)

-y=-10.52m   (10)

Multiplying by -1 each side of the equation:

y=10.52m >>>>This is the height of the building

3 0
3 years ago
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