Answer the following question according to formal grammatical rules.

Practice 1. A car travels 600 m in 30 s. what is its average speed? Why is its actual speed usually different from its average s

Sunny_sXe [5.5K]

Answer:

hi is

Explanation:

Ans. (1) For preparing vaccines, in olden days,microbes were injected in the bodies of horses ormonkeys. These laboratory animals used to makeantibodies to defend these microbes. Antibodies areproteins which can act against the disease-causinggerms. These antibodies were extracted from theblood of these animals and were used as vaccines.(2) Now-a-days with the advent of biotechnology,the vaccines are manufactured in laboratories withthe help of bacteria. For this purpose, a detailedstudy of the disease causing germ is undertaken.The genes and the DNA of such microbes arethoroughly explored. Then based on thisinformation, proteins which can act against suchmicrobes are synthetically prepared in thelaboratories. The safe vaccine is produced in such away which can defend the body against infections.3) Some types of vaccines are prepared from theextracts of germs. These germs or microbes aredeactivated and made dormant. When they areinjected in the body of a person, they initiate thedefending action. The body of such vaccinatedperson, already develops the antibodies in his or herbody. When in future, this person is again attackedby similar germs the defence starts immediately andthe person does not become sick.

7 0

3 years ago

Read 2 more answers

A 99.5 N grocery cart is pushed 12.9 m along an aisle by a shopper who exerts a constant horizontal force of 34.6 N. The acceler

Romashka [77]

1) 9.4 m/s

First of all, we can calculate the work done by the horizontal force, given by

W = Fd

where

F = 34.6 N is the magnitude of the force

d = 12.9 m is the displacement of the cart

Solving ,

W = (34.6 N)(12.9 m) = 446.3 J

According to the work-energy theorem, this is also equal to the kinetic energy gained by the cart:

$W=K_f - K_i$

Since the cart was initially at rest, $K_i = 0$ , so

$W=K_f = \frac{1}{2}mv^2$ (1)

where

m is the of the cart

v is the final speed

The mass of the cart can be found starting from its weight, $F_g = 99.5 N$ :

$m=\frac{F_g}{g}=\frac{99.5 N}{9.8 m/s^2}=10.2 kg$

So solving eq.(1) for v, we find the final speed of the cart:

$v=\sqrt{\frac{2W}{m}}=\sqrt{\frac{2(446.3 J)}{10.2 kg}}=9.4 m/s$

2) $2.51\cdot 10^7 J$

The work done on the train is given by

W = Fd

where

F is the magnitude of the force

d is the displacement of the train

In this problem,

$F=4.28 \cdot 10^5 N$

$d=586 m$

So the work done is

$W=(4.28\cdot 10^5 N)(586 m)=2.51\cdot 10^7 J$

3) $2.51\cdot 10^7 J$

According to the work-energy theorem, the change in kinetic energy of the train is equal to the work done on it:

$W=\Delta K = K_f - K_i$

where

W is the work done

$\Delta K$ is the change in kinetic energy

Therefore, the change in kinetic energy is

$\Delta K = W = 2.51\cdot 10^7 J$

4) 37.2 m/s

According to the work-energy theorem,

$W=\Delta K = K_f - K_i$

where

$K_f$ is the final kinetic energy of the train

$K_i = 0$ is the initial kinetic energy of the train, which is zero since the train started from rest

Re-writing the equation,

$W=K_f = \frac{1}{2}mv^2$

where

m = 36300 kg is the mass of the train

v is the final speed of the train

Solving for v, we find

$v=\sqrt{\frac{2W}{m}}=\sqrt{\frac{2(2.51\cdot 10^7 J)}{36300 kg}}=37.2 m/s$

7 0

4 years ago

Can someone help me fill in the two boxes.

puteri [66]

Answer:

Explanation:

I believe what you're looking for is :

Opposites

Density

Could be wrong but I think so.

7 0

3 years ago

The force acting between two charged particles a and b is 5.2 x 10^-5 newtons. Charges a and b are 2.4 x 10^-2 apart. If the cha

Aneli [31]

4.62x10^-11
hope this helped!

5 0

4 years ago

The speed of light in cubic zirconia

schepotkina [342]

The index of refraction for the cubic zirconia at the given speed of light is 2.16.

The given parameters:

<em>Speed of light in Cubic zirconia, v = 1.39 x 10⁸ m/s</em>
<em>Speed of light in air, c = 3.0 x 10⁸ m/s.</em>

The index of refraction for the cubic zirconia is the ratio of the speed of light in air to speed of light in cubic zirconia and it is calculated as follows;

$\eta = \frac{c}{v} \\\\\eta = \frac{3\times 10^8}{1.39 \times 10^8} \\\\\eta = 2.16$

Thus, the index of refraction for the cubic zirconia at the given speed of light is 2.16.

Learn more about index of refraction here: brainly.com/question/10729741

6 0

3 years ago