No, because with the parentheses, you distribute the 2 to both the x and the 5, making that equation 2x-10
44 that's a tricky question at first i thought it was -1 lol
Answer:
The area is:
, option b.
Step-by-step explanation:
Rectangular area:
The area of a rectangular space is given bt the multiplication of its measures.
Area of the roof:
Dimensions of 10x + 8 and 8x + 6. So
![A_{r} = (10x+8)(8x+6) = 80x^2 + 60x + 64x + 48 = 80x^2 + 124x + 48](https://tex.z-dn.net/?f=A_%7Br%7D%20%3D%20%2810x%2B8%29%288x%2B6%29%20%3D%2080x%5E2%20%2B%2060x%20%2B%2064x%20%2B%2048%20%3D%2080x%5E2%20%2B%20124x%20%2B%2048)
Area of the skylight:
Dimensions of x + 5 and 3x + 4. So
![A_{s} = (x+5)(3x+4) = 3x^2+4x+15x+20 = 3x^2 + 19x + 20](https://tex.z-dn.net/?f=A_%7Bs%7D%20%3D%20%28x%2B5%29%283x%2B4%29%20%3D%203x%5E2%2B4x%2B15x%2B20%20%3D%203x%5E2%20%2B%2019x%20%2B%2020)
What is the area of the remaining roof after the skylight is built?
Total subtracted by the skylight, which is a subtraction of a polynomial, in which we subtract the like terms. So
![A_{r} - A_{s} = 80x^2 + 124x + 48 - (3x^2 + 19x + 20) = 80x^2 - 3x^2 + 124x - 19x + 48 - 20 = 77x^2 + 105x + 28](https://tex.z-dn.net/?f=A_%7Br%7D%20-%20A_%7Bs%7D%20%3D%2080x%5E2%20%2B%20124x%20%2B%2048%20-%20%283x%5E2%20%2B%2019x%20%2B%2020%29%20%3D%2080x%5E2%20-%203x%5E2%20%2B%20124x%20-%2019x%20%2B%2048%20-%2020%20%3D%2077x%5E2%20%2B%20105x%20%2B%2028)
The area is:
, option b.
First, find out what the greatest common factor is between 2, 4, and 5.
<span>This is 20. So any number divisible by 20 is also divisible by 2, 4, and 5. </span>
<span>Now we find the list of numbers that are multiples of 20 between 67 and 113. </span>
<span>The solutions are: </span>
<span>80 and 100.</span>