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HACTEHA [7]
1 year ago
5

What is the slope of (-3,-2) and (1,-2)

Mathematics
1 answer:
irga5000 [103]1 year ago
4 0

Answer

Slope = 0

Explanation

For a straight line, the slope of the line can be obtained when the coordinates of two points on the line are known. If the coordinates are (x₁, y₁) and (x₂, y₂), the slope is given as

Slope=m=\frac{Change\text{ in y}}{Change\text{ in x}}=\frac{y_2-y_1}{x_2-x_1}

For this question,

(x₁, y₁) and (x₂, y₂) are (-3, -2) and (1, -2)

x₁ = -3

y₁ = -2

x₂ = 1

y₂ = -2

So,

\text{Slope = }\frac{-2-(-2)}{1-(-3)}=\frac{-2+2}{1+3}=\frac{0}{4}=0

Hope this Helps!!!

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The answer to your question is 8*5*4.
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Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 3x 1 f(x) = 3x2 11x – 1
eimsori [14]

The correct option is b.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

<h2>Leading coefficient </h2>

The leading coefficient of an equation is a coefficient of the term having the highest power in the equation.

Given options:

a.)  f(x) = -12x^2+3x+1 \\

b.)  f(x) = 3x^2+11x-12 \\

c.)  f(x) = 12x^2+3x+3\\

d.)  f(x) = 3x -12.

<h3 /><h3>Solution</h3>

As it is given that the leading coefficient of the equation is 3. therefore, the value of the 'a' in the general quadratic equation is 3,

3x²+bx+c,

Also, the value of the constant is -12, therefore, the value of c is -12,

3x²+bx-12

From all the given options the only feasible option is b only.

Hence, the correct option is b.

Learn more about Quadratic Equation:

brainly.com/question/2263981

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