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lyudmila [28]
3 years ago
11

HELP PLEASE I DON'T UNDERSTAND

Mathematics
2 answers:
natali 33 [55]3 years ago
8 0

Answer:

Step-by-step explanation:

First thing you need to do is to check if the sample data has also that 40% cycling boys, since the information you are given is not exact is "about 40%".

I did it counting in excel so not to miscount by accident, and the result was 54 numbers bellow 4 and 150 total numbers.

That comes down to 54/150 or 0.36, so in this particular set of data only 36% of the boys commute by cycle.

Now, this gives us a probability of 36% of finding a boy who commutes by bicycle on the first pick, but we want to know the probability of 3 failures and then a success. This is represented by p=0.36 and q=0.64, where q is the probability of failure on the first try.

This means that the event will occur on the first trial with probability p. If that fails, then it will occur on the next trial with a probability of (1−p)p or q*p. If that also fails, then continuing on, the probability of the event happening on the third trial is (1-p)^{2}p or q^{2} p.  If we go on and on we can see that the probability of the first success on the nth trial is (1-p)^{n}p or q^{n}p. If n=4 then the probability would be:

P=q^{4}p=0.64^{4} *0.36=0.1678*0.36=0.0604

P=6.04%

Leno4ka [110]3 years ago
5 0
If I counted correctly, the answer would be 52/150. You just need to simplify the fraction. I'll recount soon, and update if it changes.
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A c ompany purchased 3,128 bottles of water.Each departments needs 55 bottles.Which compatible numbers provide a better estimate
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Answer:

3,000 divided 60 are the compatible numbers, and the estimate is 50.

Step-by-step explanation:

Compatible numbers can be described as numbers which are close in value to the actual numbers and can easily be added, subtracted, multiplied, or divided mentally.

From the question, 3,000 divided 60 are the compatible numbers that provide a better estimate for the number of departments that can get the bottles because 55 can be rounded up to 60.

The estimate will therefore be as follows:

Estimate = 3,000 / 60 = 50

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2 years ago
Another way to write g(h(x)) is<br><br> (gOh)(x)<br> (hog)(x)
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A. Another way to write g(h(x)) is (g×h)(x)

Step-by-step explanation:

Hope this helps!

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7 0
1 year ago
Is y=150x proportional?
daser333 [38]

Answer:

yes

Step-by-step explanation:

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3 years ago
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A. Create a set of 5 points that are very close together and record the standard deviation. Next, add a sixth point that is far
defon

Answer: The addition of the new point alters the previous standard deviation greatly

Step-by-step explanation:

Let the initial five points be : 2 3 4 5 and 6. In order to calculate the standard deviation for this data, we will need to calculate the mean first.

Mean = summation of scores/number of scores.

The mean is therefore: (2+3+4+5+6)/5 = 20/5 = 4.

We'll also need the sum of the squares of the deviations of the mean from all the scores.

Since mean = 4, deviation of the mean from the score "2" = score(2) - mean (4)

For score 3, it is -1

For 4, it's 0

For 5 it's 1

For 6 it's 2.

The squares for -2, -1, 0, 1, and 2 respectively will be 4, 1 , 0, 1, 4. Summing them up we have 10 i.e (4+1+0+1+4=10).

Calculating the standard deviation, we apply the formula:

√(summation of (x - deviation of mean)^2)/N

Where N means the number of scores.

The standard deviation = √(10/5) = 1.4142

If we add another score or point that is far away from the original points, say 40, what happens to the standard deviation. Let's calculate to find out.

i.e we now have scores: 2, 3, 4, 5, 6 and 40

We calculate by undergoing same steps.

Firstly mean. The new mean = (2+3+4+5+6+40)/6 = 60/6 = 10.

The mean deviations for the scores : 2, 3, 4, 5, 6 and 40 are -8, -7, -6, -5, -4 and 30 respectively. The squares of these deviations are also 64, 49, 36, 25, 16 and 900 respectively as well. Their sum will then be 1090. i.e. (64+49+36+25+16+900 = 1090).

The new standard deviation is then=

√(1090/6)

= √181.67

= 13.478.

It's clear that the addition of a point that's far away from the original points greatly alters the size of the standard deviation as seen /witnessed in this particular instance where the standard deviation rises from 1.412 to 13.478

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