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kicyunya [14]
1 year ago
7

Pls help with number 7,8,9 and 10

Mathematics
1 answer:
ella [17]1 year ago
7 0

The answers to all the subparts of the multiplication problem are shown:

  • 185 × 24 = 4440
  • 1288 × 33 = 42504
  • 6301 × 47 = 296147
  • 3440 × 75 = 285000

<h3>What is multiplication?</h3>
  • Multiplying in math is the same as adding equal groups.
  • The number of items in the group grows as we multiply.
  • Parts of a multiplication issue include the product, the two factors, and the product.
  • The factors in the multiplication problem 6 x 9 = 54 are the numbers 6 and 9, and the product is the number 54.

So, multiplication of the numbers:

  • 185 × 24 = 4440
  • 1288 × 33 = 42504
  • 6301 × 47 = 296147
  • 3440 × 75 = 285000

(Refer to the images attached below for calculations)

Therefore, the answers to all the subparts of the multiplication problem are shown:

  • 185 × 24 = 4440
  • 1288 × 33 = 42504
  • 6301 × 47 = 296147
  • 3440 × 75 = 285000

Know more about multiplication here:

brainly.com/question/10873737

#SPJ13

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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

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The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

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3 years ago
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ivolga24 [154]

Answer:

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Step-by-step explanation:

i did it on a paper just don't want to write cause its going to be to much to write hope this helps good luck

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