Answer:
A) the ammeter is x
B)
- voltage across R₁ (left resistor) = 0.75 V
- voltage across the right one = 0.3 V
C) 1.05 V
Explanation:
From the diagram attached below;
A) Assuming the homes were wired in series, and one of the homes face short circuit then all the houses would face power cut but it doesn't happen. So they must be connected in parallel.
Therefore; The ammeter is connected in series, Hence, the ammeter is x and the voltmeter must be z.
B)
Given that:
x = 0.15 A
z = 0.3 V
Resistor (R) on the left = 5 ohms
Then, voltage across R₁ (left resistor) = 5×(x)
= 5×0.15
= 0.75 V
voltage across the right one = z = 0.3 V
C)
The total voltage of battery = 0.75+0.3 = 1.05 V
Answer:
The load has a mass of 2636.8 kg
Explanation:
Step 1 : Data given
Mass of the truck = 7100 kg
Angle = 15°
velocity = 15m/s
Acceleration = 1.5 m/s²
Mass of truck = m1 kg
Mass of load = m2 kg
Thrust from engine = T
Step 2:
⇒ Before the load falls off, thrust (T) balances the component of total weight downhill:
T = (m1+m2)*g*sinθ
⇒ After the load falls off, thrust (T) remains the same but downhill component of weight becomes m1*gsinθ .
Resultant force on truck is F = T – m1*gsinθ
F causes the acceleration of the truck: F= m*a
This gives the equation:
T – m1*gsinθ = m1*a
T = m1(a + gsinθ)
Combining both equations gives:
(m1+m2)*g*sinθ = m1*(a + gsinθ)
m1*g*sinθ + m2*g*sinθ =m1*a + m1*g*sinθ
m2*g*sinθ = m1*a
Since m1+m2 = 7100kg, m1= 7100 – m2. This we can plug into the previous equation:
m2*g*sinθ = (7100 – m2)*a
m2*g*sinθ = 7100a – m2a
m2*gsinθ + m2*a = 7100a
m2* (gsinθ + a) = 7100a
m2 = 7100a/(gsinθ + a)
m2 = (7100 * 1.5) / (9.8sin(15°) + 1.5)
m2 = 2636.8 kg
The load has a mass of 2636.8 kg
The liver, because its liver cancer.. lol
The liver filters your blood, without it, your blood will stay 'dirty' and cannot do its jobs like it usually should be
