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Novay_Z [31]
3 years ago
11

An ice boat is coasting along a frozen lake. Friction between the ice and the boat is negligible, and so is air resistance. Noth

ing is propelling the boat. From a bridge someone jumps straight down and lands in the boat, which continues to coast straight ahead. (a) Does the horizontal momentum of the boat change? (b) Does the speed of the boat increase, decrease, or remain the same? Explain.
Physics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

(A) No

(B) Speed decreases

Explanation:

(A) since there is nothing propelling the boat and the friction between the ice and the boat and also air resistance is negligible the net force of the system in the horizontal direction is zero and hence there is no change in the horizontal momentum of the boat.

(B) Since the person had not velocity in the horizontal direction before landing on the boat but now has one after landing on the boat, the speed of the boat will decrease because the momentum has to be conserved (remember there is no change in it).

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Two coils are wound around the same cylindrical form. When the current in the first coil is decreasing at a rate of -0.245 A/s ,
Airida [17]

Answer:

Complete question:

c.If the current in the second coil increases at a rate of 0.365 A/s , what is the magnitude of the induced emf in the first coil?

a.M= 6.53\times10^{-3} H

b.flux through each turn = Ф = 4.08\times10^{-4} Wb

c.magnitude of the induced emf in the first coil = e= 2.38\times10^{-3} V

Explanation:

a. rate of current changing = \frac{di}{dt}=[tex]M=\frac{1.60\times10^{-3} V}{0.240\frac{A}{s} }}[/tex]

  Induced emf in the coil =e= 1.60\times10^{-3} V

  For mutual inductance in which change in flux in one coil induces emf in the second coil given by the farmula based on farady law

     e=-M\frac{di}{dt}

     M=\frac{e}{\frac{di}{dt} }

     M=\frac{1.60\times10^{-3} }{-0.245}

   M= 6.53\times10^{-3} H

b.

  Flux through each turn=?

  Current in the first coil =1.25 A

   Number of turns = 20

       using   MI = NФ

     flux through each turn = Ф =  \frac{6.53\times10^{-3}\times1.25}{20}

   flux through each turn = Ф = 4.08\times10^{-4} Wb

c.

   second coil increase at a rate = 0.365 A/s

  magnitude of the induced emf in the first coil =?

 using   e=-M\frac{di_{2} }{dt}

            e= 6.53\times10^{-3} \times 0.365

magnitude of the induced emf in the first coil = e= 2.38\times10^{-3} V

4 0
3 years ago
Energy that is the sum of potential and kinetic energy is
Pani-rosa [81]

Answer:

The correct answer would be B.

Explanation:

I believe the answer is B because for electrical energy you would need electric charges to be moved by kinetic energy.

3 0
3 years ago
Earth has a radius of 6370 km what is earth's mass?
Oliga [24]

Answer:

approx 6 × 10^24 kg is earth's mass

3 0
3 years ago
A 20.0-kg traffic light hangs midway on a cable between two poles 30.0 meters apart. If the sag in the cable is 0.40 meters, wha
hammer [34]

Answer:

the tension in each side of the cable is 3677.57 N

Explanation:

given data

traffic light = 20 kg

cable between two poles = 30 m

sag in the cable = 0.40 m

solution

by the free body diagram

tan θ = \frac{0.4}{15}    .............1

θ = 1.527 °

and

tension = mg

The net force is along x - axis is express as

T2 cosθ = T1 cosθ     .................2

so T2 - T1     ..............3

and

when we take it along y  axis  that is express as

( T1 + T2) sinθ = mg    ...................4

so by equation 3 we put here

2 × T1 sin(1.527) = 20 × 9.8  

T1 = 3677.57 N

7 0
4 years ago
n a ballistics test, a potato gun shoots a 0.34 kg potato into a 5.0 kg catching cart. The cart recoils at 3.7 m/s after catchin
Gala2k [10]

The initial velocity of the potato is 54.41 m/s.

The given parameters:

  • <em>Mass of the potato, m = 0.34 kg</em>
  • <em>Mass of the cart, m = 5.0 kg </em>
  • <em>Velocity of the recoil, u₂ = 3.7 m/s</em>

<em />

The initial velocity of the potato is calculated by applying the principle of conservation of energy as follows;

m_1u_1 = m_2 u_2\\\\u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{5 \times 3.7}{0.34} \\\\u_1 = 54.41 \ m/s

Thus, the initial velocity of the potato is 54.41 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

6 0
3 years ago
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