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julia-pushkina [17]
1 year ago
7

Carefully follow the steps to find the solution to the three equation system.

Mathematics
1 answer:
il63 [147K]1 year ago
5 0

Answer:

The answer is (1,4,2)

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Consider the equation ay'' + by' + cy = d, where a, b, c, and d are constants. (a) find all equilibrium, or constant, solutions
Orlov [11]
Rewrite equation so that it is homogeneous . 
ay'' +by' + cy = 0

Solve characteristic equation:
ar^2 +br + c = 0 \\ \\ r = \frac{(-b) \pm \sqrt{b^2 -4ac}}{2a} 

The solutions to the homogeneous equation are:
y = k_1 e^{r_1 t} + k_2 e^{r_2 t}

Finally you need the constant term in "cy" to equal 'd' to satisfy the particular solution.
y= k_1 e^{r_1 t} + k_2 e^{r_2 t} + \frac{d}{c}
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3 years ago
How do i solve this question
Ludmilka [50]

Answer:

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Step-by-step explanation:

Divide both sides by 8\pi b

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3 years ago
What is vertex of x^2+5x-3
Art [367]

\text{The vertex of}\ ax^2+bx+c:\\\\(h,\ k),\ \text{where}\ h=\dfrac{-b}{2a};\ k=f(h)=\dfrac{-(-b^2-4ac)}{4a}

\text{We have:}\\f(x)=x^2+5x-3\\\\a=1,\ b=5,\ c=-3\\\\h=\dfrac{-5}{2\cdot1}=\dfrac{-5}{2}=-2.5\\\\k=f(-2.5)=(-2.5)^2+5(-2.5)-3=6.25-12.5-3=-9.25

\text{Answer: the vertex is in}\ (-2.5;\ -9.25)

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or about a 2.4% chance.
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