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Naddika [18.5K]
1 year ago
7

The question has to do with finding the proven with the given and I’m not sure what to do

Mathematics
2 answers:
Snezhnost [94]1 year ago
8 0

The reason for ∠8 ≅ ∠4 is alternate exterior angles

The question has to do with finding the proven with the given.

We have been given line f is parallel to line g.

We need to prove angle 8 is congruent to angle 4.

From given figure we observe that line f || line g and these parallel lines are intersected by a transversal.

And the angle 8 are angle 4 are alternate exterior angles.

We know that alternate exterior angles are congruent.

so, ∠8 ≅ ∠4

Therefore, the reason for ∠8 ≅ ∠4 is alternate exterior angles

Learn more about alternate exterior angles here:

brainly.com/question/2279752

#SPJ1

Oduvanchick [21]1 year ago
7 0

Using the two parallel line theorems we proved that ∠8 ≅ ∠4.

In the given question,

Given: f || g

Prove: ∠8 ≅ ∠4

We using given diagram in proving that ∠8 ≅ ∠4

Since f || g, by the Corresponding Angles Postulate which states that "When a transversal divides two parallel lines, the resulting angles are congruent." So

∠8≅∠6

Then by the Vertical Angles Theorem which states that "When two straight lines collide, two sets of linear pairs with identical angles are created."

∠6≅∠4

Then, by the Transitive Property of Congruence which states that "All shapes are congruent to one another if two shapes are congruent to the third shape."

∠8 ≅ ∠4

Hence, we proved that ∠8 ≅ ∠4.

To learn more about parallel line theorems link is here

brainly.com/question/27033529

#SPJ1

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3 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

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