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GalinKa [24]
3 years ago
9

Find the arc of the semicircle(diameter is 12)

Mathematics
1 answer:
Alchen [17]3 years ago
4 0

Answer:

18.849

Step-by-step explanation:

\frac{180}{360}  \times 2\pi \:  \times 6 \\  \frac{1}{2}  \times 2 \times \pi \times 6 \\  \pi \times 6  \\ = 18.849

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Help help help help help
e-lub [12.9K]

Answer: E: 100%

Step-by-step explanation:

If the class average is currently 70% and she wants to increase it by 10% every week for 3 weeks, 10×3=30% and 70+30= 100%.

PS- It would mean the world to me if you could mark me brainliest!

I am not a professional, I am simply using prior knowledge!

7 0
3 years ago
Which function is most closely represented by the graph ?
Helen [10]

Answer:

3 + 3/4x

Step-by-step explanation:

it is 3 up and 4 left so y over x for the the slope. mx +b

3 0
3 years ago
Is y =3/4x +2 And -6x+8y=16 parallel or coincident
Rudiy27

Answer:

parallel

Step-by-step explanation:

y=3/4x+2

Multiply the equation by 8:

8y=6x+16

(8y-6x)=16

and you can clearly see that they're same

4 0
3 years ago
A girl can run 6 2/3 metres in one second. How long will it take her to run 100 metres?
Crank

Answer:

15 seconds

Step-by-step explanation:

How did i get this answer? It is apparent that the girl is capable of running 6 2/3 metres per one second and she must run 100 metres.

First, let's convert 2/3 into a decimal so that it is easier to calculate later. 2/3=0.667 (you can also just do 2 divide by 3 and will end up with the same number)

Now our numbers are 6.667 and 100. Let's divide 100 by 6.667 which estimates to 15

7 0
2 years ago
Read 2 more answers
Un submarino se encuentra 50m por debajo del nivel del mar y comienza a subir 2m cada 5 minutos ¿a que profundidad se encuentra
Trava [24]

Answer:

a) El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

Step-by-step explanation:

a) De acuerdo con el enunciado, la cantidad de metros ascendidos por el submarino es directamente proporcional al tiempo, entonces la profundidad del submarino a la hora de haber comenzado el ascenso se obtiene mediante la siguiente relación lineal:

h = 50\,m - \frac{2\,m}{5\,min}\times 60\,min

h = 26\,m

El submarino se encuentra a una profundidad de 26 metros una hora después de haber comenzado el ascenso.

b) En primer lugar, calculamos el tiempo total del viaje mediante la siguiente relación:

\frac{2\,m}{5\,min} = \frac{50\,m}{t}

t = 50\,m\times \frac{5\,min}{2\,m}

t = 125\,min (2\,h\,5\,min)

El tiempo faltante para alcanzar la superficie se calcula mediante la siguiente sustracción:

\Delta t = 125\,min - 60\,min

\Delta t = 65\,min (1\,h\,5\,min)

Al submarino le falta 1 hora y 5 minutos para llegar a la superficie.

7 0
3 years ago
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