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1 year ago

Is collecting pennies dependent or an independent events?

Mathematics

1 answer:

Strike441 [17]1 year ago

8 0

Collecting pennies can either be a dependent or an independent events based on the scenario.

<h3>How to illustrate the information?</h3>

Events classified as independent do not depend on other events for their occurrence. For instance, if we toss a coin in the air and it lands on head, we can toss it again and this time it will land on tail.

A coin toss is an illustration of an autonomous occurrence. With each toss of the coin, there is an equal probability (0.5) of either heads or tails occurring, presuming that the coin is fair and can only land on heads or tails. It doesn't matter if the coin came up heads on the prior toss.

In conclusion, collecting pennies can either be a dependent or an independent events based on the scenario.

Learn more about events on:

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How would I solve this equation for mass (m)?

zaharov [31]

Simple...

you have: $F= \frac{G m^{2} }{ d^{2} }$

You want to find m-->>>

1.)Isolate m

$d^{2} *F= \frac{G m^{2} }{ d^{2} } * d^{2}$

Leaving you with...

F* $d^{2}$ = $G m^{2}$

Keep isolating m-->>>

$F* d^{2} =G m^{2}$

$\frac{F* d^{2} }{G} = \frac{G m^{2} }{G}$

Square root to solve what just m is-->>>

$\sqrt{ \frac{F* d^{2} }{G} } = \sqrt{ m^{2} }$

= $\sqrt{ \frac{F* d^{2} }{G} } =m$

That is how you solve for m...

Thus, your answer.

7 0

3 years ago

In this activity, you'll calculate a probability and use it to predict the result of repeating a simple chance-based trial many

kompoz [17]

1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
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(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5

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3 years ago

Read 2 more answers

Find the indicated values where g(t)=t^2-t and f(x)=1+x g(f(0))+f(g(0))

Blababa [14]

Answer:

Step-by-step explanation:

First find f(0) and g(0). These are the values where x=0 in each function.

f(0) = 1+0 = 1

g(0) = 1^2 - 1 = 1-1 = 0

So f(0) = 1 and g(0) = 0.

Now substitute f(0) = 1 into g(t).

g(1) = 1^2 -1 = 1-1 = 0.

So g(f(0)) = 0.

Now substitute g(0) = 0 into f(t).

f(0) = 1 + 0 = 1.

So f(g(0)) = 1.

Add the values 0 and 1 to get 0+1 = 1.

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3 years ago

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Simplify the expression 12c-c

Klio2033 [76]

Answer:

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Think of it like 12c-1c.

When it is c by itself, then it is just 1c.

Subtract 12-1, get 11.

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3 years ago

Alberto measures the length of a piece of wire to be 105 cm. The actual length of the wire was 120 cm. What was the percent erro

natali 33 [55]

Answer:

12.5%

Step-by-step explanation:

105 over 120 is the fraction that he got so you subtract 105 from 120 to get how much he missed. 120-105=15

He miscalculated by 15 cm out of the total of 120, 15/ 120

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