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My name is Ann [436]
1 year ago
14

Factor the given expression by determining any common monomial factorsthat may exist 6k2m - 3k + 9km2 - 12k2m2

Mathematics
1 answer:
Varvara68 [4.7K]1 year ago
3 0

ANSWER

=3k\left(3m^2+2km-4km^2-1\right)

EXPLANATION

Given;

6k^2m-3k+9km^2-12k^2m^2

The common factor is 3k;

Hence, factor out the common term;

\begin{gathered} =3k\left(2mk-1+3m^2-4m^2k\right) \\ =3k\left(3m^2+2km-4km^2-1\right) \end{gathered}

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What happens to the value of the expression b-1 as b increases
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It increases

Step-by-step explanation:

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3 years ago
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A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

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7 0
3 years ago
What is the simplified value of the exponential expression 16 Superscript one-fourth?
pochemuha

<u>Answer: </u>

The value of the exponential expression 16^{\frac{1}{4}} is 2  

<u>Solution:</u>

16 superscript one-fourth= 16^{\frac{1}{4}}

As per the problem,  

We have to find the value of 16^{\frac{1}{4}}  

16 in terms of 2 can be written as 2\times2\times2\times2

= (2 \times 2 \times 2 \times 2)^{\frac{1}{4}}

=\left(2^{4}\right)^{\frac{1}{4}}

As per the exponential rule, a^{(m)^{n}}=a^{m \times n}

=2^{4 \times \frac{1}{4}}

Here, 4\times\frac{1}{4}=1

= 2^{1}

= 2

Hence, the value is 2.

9 0
2 years ago
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