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beks73 [17]
3 years ago
5

Please help

Mathematics
1 answer:
lianna [129]3 years ago
6 0

Answer:

there is no consistent relationship and has no real correlation

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Need help plz!!!?!?!?!?
Kipish [7]

Answer:

54yd

Step-by-step explanation:

Area for the rectangle=8×6

=48yrd

area for the triangle=1/2×4×3

=6yd

Total area=48+6=54yd

3 0
3 years ago
sandy is upgrading her internet service fast charges $60 for installation and $50.45 per month quick internet has free installat
seraphim [82]
Answer:
60+50.45x=57.95x

Cost of Fast Internet:
$60 for installation and $50.45 per month for months =

Cost of Quick Internet:
Free installation and $57.95 per month for months =

We want to know in how many months BOTH COSTS WOULD BE SAME. So we EQUATE the expressions for both. We have:

This equation can be solved for x to find the number of months for which the internet service would cost the same.

Read more on Brainly.com - brainly.com/question/893458#readmore
4 0
3 years ago
Cystic fibrosis (CF) is a hereditary lung disorder that often results in death. It can be inherited only if both parents are car
OLEGan [10]

Answer:

0.9959 = 99.59% probability that a randomly chosen person of European ancestry does not carry an abnormal CF gene given that he /she tested negative.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Tested negative

Event B: Does not carry an abdornal CF gene.

Probability of a negative test:

10% of 1/25 = 0.04 = 4%

100% of 100 - 4 = 96%. So

P(A) = 0.1*0.04 + 1*0.96 = 0.964

Negative test and not carrying an abdornal gene:

100% of 96%. So

P(A \cap B) = 1*0.96 = 0.96

Compute the probability that a randomly chosen person of European ancestry does not carry an abnormal CF gene given that he /she tested negative.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.96}{0.964} = 0.9959

0.9959 = 99.59% probability that a randomly chosen person of European ancestry does not carry an abnormal CF gene given that he /she tested negative.

8 0
3 years ago
Helpp please 10 points ok
icang [17]

The correct answer is :

\frac{13}{50}

3 0
3 years ago
Read 2 more answers
For the linear function f(x) = -2x+1 , find the following
Leya [2.2K]

Given:

The function is:

f(x)=-2x+1

To find:

a. Slope and Y-intercept.

b. Is the function increasing, decreasing, or constant, justify your answer.

c. Graph the function, label x, and y-intercepts.

Solution:

a. We have,

f(x)=-2x+1                  ...(i)

The slope intercept form of a line is:

y=mx+b                    ...(ii)

Where, m is the slope and b is the y-intercept.

On comparing (i) and (ii), we get

m=-2,b=1

Therefore, the slope of the line is -2 and the y-intercept is 1.

b. If the slope of a linear function is negative, then the function is decreasing.

If the slope of a linear function is positive, then the function is increasing.

If the slope of a linear function is 0, then the function is constant.

The slope of the linear function is negative.

Therefore, the function is decreasing.

c. We have,

f(x)=-2x+1

At x=0, we get

f(0)=-2(0)+1

f(0)=1

So, the y-intercept is at (0,1).

At f(x)=0, we get

0=-2x+1

2x=1

x=\dfrac{1}{2}

x=0.5

So, the x-intercept is at \left(0.5,0\right).

Plot the points (0,1), \left(0.5,0\right) and connect them by a straight line as shown below:

4 0
3 years ago
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