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TiliK225 [7]
2 years ago
13

PLEASE HELP ME.. (no links)

Mathematics
2 answers:
Gnesinka [82]2 years ago
4 0

Answer:

I think it is c

Step-by-step explanation:

iVinArrow [24]2 years ago
3 0
The answer is c I hope it helps
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Find the equation of the vertical line through (7,-3)
wlad13 [49]
X = 7
Is a vertical line that passes through (7,-3).
4 0
3 years ago
Aunt Kendra is pricing cakes for a baby shower she is throwing. She wants one large cake shaped like a duckling and also some cu
Andreas93 [3]

Answer:

$70

Step-by-step explanation:

Middletown Equation:

1c +50 = T

Sweet Shoppe Equation:

2c + 30 = T

Set equations equal to one another and solve for first for cupcakes then for cost.

1c + 50 = 2c + 30

c+ 20 = 2c

20 = c (twenty cupcakes would be ordered)

Now insert into either equation ( or both to check)

1(20) + 50 = 70

2(20)+ 30 = 70

Total cost would be $70

HOPE THIS HELPS!!!

4 0
2 years ago
If you multiply two decimals less than 1 can you predict whether the product will be less than or greater than either of the fac
ki77a [65]

I predict that the product will be less than either of the factors.

When you multiply two numbers less than ' 1 ', you are
calculating the size of a piece of a piece.  It winds up being
smaller than either of the pieces.

3 0
2 years ago
If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many
kotykmax [81]

Question:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M's from an extra-large bag looking for a red candy.

If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many M&M’s will the students need to select? (Round your answer to two decimal places.).

Answer:

If every student in the large Statistics class selects peanut M&M’s at random until they get a red candy the expected value of the number of  M&M’s the students need to select is 8.33 M&M's.

Step-by-step explanation:

To solve the question, we note that the statistical data presents a geometric mean. That is the probability of success is of the form.

The amount of repeated Bernoulli trials required before n eventual success outcome or

The probability of having a given number of failures before the first success is recorded.

In geometric distribution, the probability of having an eventual successful outcome depends on the the completion of a certain number of attempts with each having the same probability of success.

If the probability of each of the preceding trials is p and the kth trial is the  first successful trial, then the probability of having k is given by

Pr(X=k) = (1-p)^{k-1}p  

The number of expected independent trials to arrive at the first success for a variable Xis 1/p where p is the expected success of each trial hence p is the probability for the red and the expected value of the number of trials is 1/p or where p = 12 % which is 0.12

1/p = 1/0.12 or 25/3 or 8.33.

4 0
3 years ago
I can't figure out the area. please help. I'm confused. my teacher said to solve it like a triangle
mr Goodwill [35]
Okay so if you first calculate triangle ABC
Then calculate triangle DAF + GEC
take ABC to minus the 2 triangles

8 0
3 years ago
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