Answer:
13b-12a+5 (so the last one)
Step-by-step explanation:
b-6a+12b-6a+5
13b-12a+5
Answer
Step-by-step explanation:
b)x=-1,-3
At the point when Hannah takes her first sweet from the sack, there is a 6/n chance it is orange.
This is because that there are 6 orange desserts and n desserts altogether.
When Hannah takes out her second sweet, there is a 5/(n-1) chance that it is orange.
This is because there are just 5 orange desserts let alone for an aggregate of n-1 desserts.
The possibility of getting two orange desserts in succession is the main likelihood increased by the second one: 6/n x 5/n–1
The question lets us know that the shot of Hannah getting two orange desserts is 1/3.
So: 6/n x 5/n–1 = 1/3
Now, rearrange this problem.
(6x5)/n(n-1) = 1/3
This gets to be:
30/(n² – n) = 1/3
Times by 3 on both sides:
90/(n² – n) = 1
What's more, doing likewise with (n² – n):
So (n² – n) = 90
Our answer is: n² – n – 90 = 0
Answer:
1)
2)
3)
4)Rs.36 000
Step-by-step explanation:
1)1/3+1/4=4/12+3/12
=7/12
2)remaining=12/12-7/12
=5/12
other expenses=5/12*3/5
=1/4
3)total=7/12+1/4
=7/12+3/12
=10/12
=5/6
remaining=6/6-5/6
=1/6
fraction of the salary=1/6*2
=2/12
4)1/6=rs.6000
6/6=rs,36 000
"Given that he is male" is an important phrase here. The "given" in any probability problem is often important. This tells us "only focus on the males" because we know 100% that whoever we picked, the person is a male.
So we only focus on the "male" column. Use a highlighter to mark this column or cover up the other values if they are too distracting. There are 51 males total (bottom row) and 39 males had a flu shot (top row)
Divide the two values: 39/51 = (13*3)/(17*3) = 13/17
Answer: 13/17
