don't know how to do this kind of math anymore so if someone could me it would be really great 2.54 x .12000 =
1 answer:
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Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater
so "b" is "4 more than 5 times" "a"
so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4
so.. whatever "a" is, "b" is 5a+4
now, their sum is 22, as opposed to "zz" hehe
so
solve for "a", to see what the smaller one is
what's "b"? well, b = 5a + 4
hmm say "a" is the smaller, and "b" the greater
so "b" is "4 more than 5 times" "a"
so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4
so.. whatever "a" is, "b" is 5a+4
now, their sum is 22, as opposed to "zz" hehe
so
solve for "a", to see what the smaller one is
what's "b"? well, b = 5a + 4
which means there is some integer
Because
We have
1, 42
2, 21
3, 14
6, 7
which is to say there are also four corresponding choices for
9, 378
18, 189
27, 126
54, 63
whose sums are:
387
207
153
117
So the least possible value of