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Alborosie
1 year ago
15

Endure all, a manufacturer of batteries claims that the lifetime of their batteries is normally distributed with a mean of 500 h

ours and a standard deviation of 40 hours. What is the probability that an endure all battery selected at random will last more than 550 hours?.
Mathematics
1 answer:
ycow [4]1 year ago
7 0

Based on the z-score, an Endure All battery selected at random has a 10.56% chance of lasting more than 550 hours.

<h3>What are z-scores?</h3>

How closely a value relates to the mean of a set of values is expressed by a Z-score.

The Z-score is created using standard deviations from the mean.

A data point's total value is equal to the mean value when the Z-score of the data point is equal to 0.

So, in order to determine how far the raw score deviates from the mean, the Z score is used.

The following steps are used to determine the Z score:

z = (x - μ)/σ

We know that:  x > 550 and μ = 500, σ = 40

z = 550 - 500 / 40

z = 1.25

The graph of the normal distribution indicates:

P(z > 1.25) = 1 - P(z < 1.25)

P(z > 1.25) = 1 - 0.8944

P(z > 1.25) = 0.1056

Therefore, based on the z-score, an Endure All battery selected at random has a 10.56% chance of lasting more than 550 hours.

Know more about the z-scores here:

brainly.com/question/25638875

#SPJ4

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Answer: B

Step-by-step explanation:

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7 0
3 years ago
2 u + 12 &lt; 23<br> 0,1 d + 8 &gt; 0<br> 3 - 4 r &gt; 7<br> 13 &lt; 2 z + 3<br> 6 ≥ 9 - 0, 15 i
BartSMP [9]

Answer:

Part 1) u< 5.5  

Part 2) d > -80

Part 3) r < -1

Part 4) z>5

Part 5) i\geq 20

Step-by-step explanation:

<u><em>The question is</em></u>

Solve each inequality for the indicated variable

Part 1) we have

2u+12

subtract 12 both sides

2u< 23-12\\2u

Divide by 2 both sides

u< 5.5

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

0.1d+8 >0

subtract 8 both sides

0.1d > -8

Divide by 0.1 both sides

d > -80

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

3-4r> 7

Subtract 3 both sides

-4r>7-3\\-4r>4

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

r < -1

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

13< 2z+3

Subtract 3 both sides

13-3

Divide by 2 both sides

5

Rewrite

z>5

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

6\geq 9-0.15i

Subtract 9 both sides

6-9\geq -0.15i\\-3\geq -0.15i

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

20\leq i

Rewrite

i\geq 20

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

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saw5 [17]

(3x+4)+(5x2-1)+(2x+6)

remove unnecessary parenthesis

3x+4+(5x2-1)+(2x+6)

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collect the like terms

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Answer:

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Answer:

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