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Alborosie
1 year ago
15

Endure all, a manufacturer of batteries claims that the lifetime of their batteries is normally distributed with a mean of 500 h

ours and a standard deviation of 40 hours. What is the probability that an endure all battery selected at random will last more than 550 hours?.
Mathematics
1 answer:
ycow [4]1 year ago
7 0

Based on the z-score, an Endure All battery selected at random has a 10.56% chance of lasting more than 550 hours.

<h3>What are z-scores?</h3>

How closely a value relates to the mean of a set of values is expressed by a Z-score.

The Z-score is created using standard deviations from the mean.

A data point's total value is equal to the mean value when the Z-score of the data point is equal to 0.

So, in order to determine how far the raw score deviates from the mean, the Z score is used.

The following steps are used to determine the Z score:

z = (x - μ)/σ

We know that:  x > 550 and μ = 500, σ = 40

z = 550 - 500 / 40

z = 1.25

The graph of the normal distribution indicates:

P(z > 1.25) = 1 - P(z < 1.25)

P(z > 1.25) = 1 - 0.8944

P(z > 1.25) = 0.1056

Therefore, based on the z-score, an Endure All battery selected at random has a 10.56% chance of lasting more than 550 hours.

Know more about the z-scores here:

brainly.com/question/25638875

#SPJ4

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\textup{Mutually events are events that cannot occur at the same time.}\\\textup{When you toss a coin you get only $head$ or only $tail$ but never both.}\\ \textup{In mathematical terms $P(A) \cup  P(B) = 0$, where $A$ and $B$ are mutually exclusive events. }\\\textup{We know the formula:}\\$$ P(A \cup B) = P(A) + P(B) - P(A \cup B) $$\\\textup{When $A$ and $B$ are mutually exclusive, it will simply be:}\\$$ P(A \cup B) = P(A) + P(B) $$\\\textup{Now given:}\\ $P(S) = 8/9$ , $P(T) = 1/10$\\

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