Answer:
The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
90% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).
Answer:
48 children performing.
Step-by-step explanation:
Well all you do is divide 144 by 3 and you will get the answer of 48.
Answer:
Mean=(46+48+51+53)/4
Mean=198/4
Mean=49.5
Step-by-step explanation:
Mean is the total amount per the total number of terms. It is also known as average.
Answer:
H0 : μ = 8.5
H1 : μ > 8.5
1 sample t test ;
Test statistic = 2.53
Pvalue = 0.994
No, we fail to reject the Null ;
There is no significant evidence to support the Claim that the mean running time of light bulb is greater Tha last year.
Step-by-step explanation:
H0 : μ = 8.5
H1 : μ > 8.5
Test statistic :
(xbar - μ) ÷ (s/sqrt(n))
(8.7 - 8.5) ÷ (0.5 / sqrt40)
Test statistic = 2.53
The Pvalue :
P(Z < 2.53) = 0.9943
Pvalue = 0.994
Decison region :
Reject H0 ; if Pvalue < α
0.9943 > 0.05 ; We fail to reject the Null
Step-by-step explanation:
Given
Hope it will help :)
