A I hope this helps <3333333333333333
Logb1=0 log b 1 = 0 . This follows from the fact that b0=1 b 0 = 1 .
logbb=1 log b b = 1 . This follows from the fact that b1=b b 1 = b .
logbbx=x log b b x = x . This can be generalized out to logbbf(x)=f(x) log b b f ( x ) = f ( x ) .
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