Answer:
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Step-by-step explanation:
Tamira invests $5,000 in an account
Rate of interest = 4%
Time = 3 years
Case 1:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 1
Formula :

A=5624.32
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
Case 2:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 2
Formula : 

A=5630.812
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
Case 3:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula : 

A=5634.125
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
Case 4:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula :

A=5636.359
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Answer:
4x+11 is the answer.
Step-by-step explanation:
( 4*2-x+3)-(3*2-5x-6)
=(8-x+3)-(6-5x-6)
=(11-x)-(0-5x)
=(11-x)-(-5x)
=11-x+5x
=11+4x
= 4x+11
Answer:
65
Step-by-step explanation:
I dont know the answer hope this helps
<span>4y - 12x = 20
4y = 12x + 20
y = 3x + 5
parallel has same slope = 3
answer
</span><span>A. Y = 3x - 1 </span>
Answer:
Step-by-step explanation:
y = -x + 3
y + 1 = -(x + 1)
y + 1 = -x - 1
y = -x - 2
x + y + 2 = 0 is the solution