Cell Differentiation
Giant sequoias can grow more than 80 meters tall! molecules they need for growth using atoms from the water and air around them. ... Plants take in molecules from water and air around them to make different molecules that can be used for energy and growth.
meristematic tissues
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Unsaturated fatty acids are a component of the phospholipids in cell membranes and help maintain membrane fluidity. The Phospholipids contain a variety of unsaturated fatty acids, when compressed, the “kinks” in their tails push adjacent phospholipid molecules away, that helps in maintain fluidity in the membrane. Unsaturated fatty acids have at least one double bond, creating a "kink" in the chain, the absence of double bonds decreases fluidity, making the membrane very strong and stacked tightly.
The ratio of saturated and unsaturated fatty acids determines the fluidity in the membrane at a temperature, at appropriate temperatures the phospholipids have enough kinetic energy to overcome the intermolecular forces holding the membrane together, which increases membrane fluidity.
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Answer:
Carrying capacity
Explanation:
Carrying capacity is the limit to which a population can grow with the resources (food, water, oxygen, habitat space, etc.) are available to support them. Once they reach the maximum population that the environment can support, they reach their carrying capacity.
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Answer: and Explanation:
A.)The reason for the different products of glycogen breakdown in the two tissues is that glucose 6-phosphotase which is
a known enzyme that brings about hydrolysis of glucose 6-phosphate as a result of the creation of a phosphate group and free glucose is not available in heart and skeletal muscle, therefore,any glucose 6-phosphotase that is produced will just enters the glycolytic pathway and get converted to lactate through pyruvate, in the absence of Oxygen O2.
B) Whenever a situation involving fight or flight arises, the concentration of glycolytic precursors becomes high in order to prepare for muscular activity. Since the membrane is impermeable to any charged species, and at the same time glucose 6-phosphotase enzyme cannot be moved through the glucose transporter, then there cannot be a release of Phosphorylated intermediates from the cell. The blood glucose level must be maintained by the liver by releasing of glucose.
glucose that is later formed from glucose 6-phosphotase then enters the bloodstream.
