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Vika [28.1K]
2 years ago
9

Copy down the calculation below and insert one pair of brackets so that the

Mathematics
1 answer:
Nookie1986 [14]2 years ago
7 0

Answer:

12+24÷(2^2+8)

Step-by-step explanation:

that should be the answer

if you struggle with questions that are like this use trial and error

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Which of the following is an extraneous solution of startroot 4 x 41 endroot = x 5? x = –8 x = –2 x = 2 x = 8
Gnom [1K]

The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.

<h3>What is an extraneous solution?</h3>

It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.

✓4x + 41 = x + 5

Square both sides

4x + 41 = x² + 10x + 25

x² + 6x - 16

x(x + 8) - 2(x + 8) = 0

x + 8 = 0

x= 0 + 8 = 8

Learn more about extraneous solution on:

brainly.com/question/295656

#SPJ4

7 0
2 years ago
Read 2 more answers
All points having an x-coordinate of 1 whose distance from the point (-3,-6) is 5
vazorg [7]

Answer:

They'll  \: be  \: on  \: the \:  circle:

(x+3)^2+(y+6)^2=25

x=1

(y+6)^2=9

y + 6 = 3

y = -3

(1,-3)

y + 6 = -3

y = -9

(1,-9)

Step-by-step explanation:

Thank \:  you!!!!!!

6 0
3 years ago
The American Water Works Association reports that the per capita water use in a single-family home is 63 gallons per day. Legacy
Debora [2.8K]

Answer:

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

df=n-1=28-1=27  

p_v =P(t_{(27)}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=60 represent the sample mean

s=8.9 represent the sample standard deviation

n=28 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 63, the system of hypothesis would be:  

Null hypothesis:\mu \geq 63  

Alternative hypothesis:\mu < 63  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=28-1=27  

Since is a one side lower test the p value would be:  

p_v =P(t_{(27)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

5 0
4 years ago
K and m are prime numbers .
PolarNik [594]

Answer:

I think k = 2 and m = 19

and I also think in order to mention the steps there must be another clue or equation

4 0
4 years ago
Help me please people
postnew [5]

Answer:

6 divided by 4=6/4 (bottom left)

Step-by-step explanation:

You're dividing a 6 meter area into 4 parts, so you're dividing 6 by 4 (6/4 m)

6 0
4 years ago
Read 2 more answers
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