Step-by-step explanation:
Circumference of a circle is 2piR
C=2piR and R=10
C=2(3.14)(10)
So the circumference is 62.8 cm
Answer:
<h2 /><h2>The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest. The IQR is often seen as a better measure of spread than the range as it is not affected by outliers. Interquartile Range. 25% of values.</h2>
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<h2>here your answer </h2>
Surface area of a sphere=4pi(r^2)
Volume of a sphere=(4/3)pi(r^3)
You need to find the r value to calculate surface area, so I'll solve for that first.
(4/3)pi(r^3)=2254pi
(4/3)(r^3)=2254
r^3=1690.5
r=(1690.5)^(1/3), around 11.9126m
Substitute this in to find surface area
A=4pi(r^2)=4pi(11.9126)^2
=1783.2818 m^2
Answer:
Step-by-step explanation:
(-1,5) (0,2)
y2= 2, y1 = 5, x2 = 0, x1 = -1
Slope m = [y2 - y1]/[x2 - x1]
m = {2 - 5}/{0+1}
m = -3/1
m = -3
And
y - y1 = m(x - x1)
y - 5 = -3(x + 1)
y - 5 = -3x - 3
y = -3x - 3 + 5
y = -3x + 2
