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asambeis [7]
3 years ago
15

How do I do this.?.?.

Mathematics
2 answers:
viktelen [127]3 years ago
3 0
108 = ( x)(48-x)
108 = 48x - x^2
48x -x^2 -108 = 0

I'm assuming you're doing solve the square right now, so you should be able to do the rest.
Karo-lina-s [1.5K]3 years ago
3 0
Okay, so we know the Perimeter is 48m and the Area is 108m²

the formulas you'll need are P = 2(w+h) and A = w*h (w = width and h = height)

so...     2(w+h) = 48               w*h = 108
            w+h = 24                   w = 108/h
            w = 24 - h                  h = 108/w
            <span>h </span>= 24 - w

Now we choose one of the variables (I'll pick w) and set the two corresponding equations equal to eachother.

w = 24 - h = 108/h

then, do some algebra to get  h² - 24h + 108 = 0

Recall that in the original question they told us that one of the sides is represented by <span>x. So, lets sub in x for h from now on. (I'll explain why at the end)

so,   x</span>² - 24x + 108 = 0

this is a qudratic equation and can be factored into (x - 18)(x - 6) = 0

set each factor equal to zero and solve for x

you get   x = 18   and   x = 6

the reason we subbed in x was because i knew we would get two answers and it might have been confusing to get two answers for h or w. With x though, you can now choose which value you want to assign to which variable.

to check this answer, you can go back to the top with the equations for perimeter and area and plug these numbers into the equation in any order and it should work.

if that all made sense, you should figure out that the dimensions will be 18m by 6m
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Use PEMDAS for this problem.
1 x 1000=   + 1000
3 x 10,000= 30,000
---------------------------
                 + 31000
                       9000
---------------------------
                 + 40000
                         800
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                                  2
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             Answer: 40,852

Hoped this helped.

~Bob Ross ®
5 0
3 years ago
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abruzzese [7]
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Emily drew a scale drawing of a house and its lot. The back patio is 42 millimeters long in the drawing. The actual patio is 27
kirill [66]

the scale factor used in Emily scale drawing is K = 1.63 mm/m

<h3>What scale did Emily use?</h3>

We know that Emily drew a scale drawing of a house and its lot.

In the scale drawing, the back patio is 42 millimeters long, and we know that the actual patio is 27 meters long.

Then the scale relates the measures 44mm and 27 meters, such that if the scale is K, we can write:

K*27m = 44mm

Solving for K, we can write:

K = (44/27) mm/m = 1.63 mm/m

So the scale factor used in Emily's scale drawing is K = 1.63 mm/m

If you want to learn more about scale factors:

brainly.com/question/25722260

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