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Yuliya22 [10]
2 years ago
6

Find the Value. Please help

Mathematics
1 answer:
Irina18 [472]2 years ago
8 0

The value of y is 36

The value of w is -13

<h3>Calculating the value of angles </h3>

From the given question, we are to determine the value of y

From the given information,

We have that line b is parallel to line c

Then,

74° + (2y + 34)° = 180°

Solve for y

(2y + 34)° = 180° - 74°

2y° + 34° = 106°

2y° = 106° - 34°

2y° = 72°

y° = 72°/2

y° = 36°

Hence, y = 36

In the second diagram,

72° + ∠ACB + ∠BCD = 180° (<em>Sum of angles on a straight line</em>)

From the given information,

BC bisects ∠ACD

Thus,

∠ACB = ∠BCD

Then, we can write that

72° + ∠BCD + ∠BCD = 180°

72°  + 2 × ∠BCD = 180°

2 × ∠BCD = 180° - 72°

2 × ∠BCD = 108°

∠BCD = 108°/2

∠BCD = 54°

Since line j is parallel to line k

Then,

(2w + 80)° = ∠BCD (<em>Corresponding angles</em>)

(2w + 80)° = 54°

2w° + 80° = 54°

2w° = 54° - 80°

2w° = -26°

w° = -26°/2

w° = -13°'

Hence, w = -13

Learn more on Calculating the value of angles here: brainly.com/question/21369105

#SPJ1

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Please help!
Gemiola [76]

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

In this exercise we must apply the definition of derivative, which is described below:

f'(x) =  \lim_{x \to 0} a_n \frac{f(x+h)-f(x)}{h} (1)

If we know that f(x) = 2\cdot x^{2}-9, then the derivative of the expression is:

f'(x) =  \lim_{h \to 0} \frac{2\cdot (x+h)^{2}-9-2\cdot x^{2}+9}{h}

f'(x) = 2\cdot \lim_{h \to 0} \frac{x^{2}+2\cdot h\cdot x + h^{2}-2\cdot x^{2}}{h}

f'(x) = 2\cdot  \lim_{h \to 0} 2\cdot x + h

f'(x) = 4\cdot x

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

We kindly invite to check this question on derivatives: brainly.com/question/23847661

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Step-by-step explanation:

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