The slope of a line which is perpendicular to the line whose equation is 6 x + y = 8 as given in the task content is; 1/6
<h3>What is the slope of the line perpendicular to that whose equation is as given in the task content above?</h3>
It follows from the task content that the slope of the line which is perpendicular to the line whose equation is 6 x + y = 8.
First, by rewriting the given equation such that it takes the slope-intercept form; y = mx + c; we have;
y = -6x + 8.
Recall that the slopes of a pair of lines which are perpendicular to each other are related such that;
m1 × m2 = -1 where m1 = -6.
Therefore, the slope of the second equation as required will be;
m2 = -1/(-6)
m2 = 1/6.
Ultimately, slope of a line which is perpendicular to the line whose equation is 6 x + y = 8 as given in the task content is; 1/6.
Read more on slope of perpendicular lines;
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