The width of the right rectangular prism is 4.8. You multiply 7.35 by 16.25 and then you divide 573.3 by that answer. So, 573.3 ÷ 119.4375 = 4.8. Hope this helped
I think the correct answer is 17
Hello from MrBillDoesMath!
Answer:
x = log5 / ( (1/2)log6 + log5)
approximately 0.642
Discussion:
Take the logarithm of both sides ( to "pull" the exponents down so we can work on them!)
6^(x/2)) = 5^(1-x)
log ( 6^(x/2)) = log (5^(1-x)) => using log (a^n) = n log a
(x/2) log6 = (1-x) log5 => add x log5 to both sides
(x/2) log6 + xlog5 = log5 - xlog5 + xlog5 =>
(x/2) log6 + xlog5 = log5 => factor x from the lhs
x ( (1/2) log6 + log5) = log5 =>
x = log5 / ( (1/2)log6 + log5)
The above can be further simplified but that's as far as I want to take it.The value of x is approx equal to 0.642
Thank you,
MrB
5(x-2)+7=65-4(5x-8)
We move all terms to the left:
5(x-2)+7-(65-4(5x-8))=0
We multiply parentheses
5x-(65-4(5x-8))-10+7=0
We calculate terms in parentheses: -(65-4(5x-8)), so:
65-4(5x-8)
determiningTheFunctionDomain
-4(5x-8)+65
We multiply parentheses
-20x+32+65
We add all the numbers together, and all the variables
-20x+97
Back to the equation:
-(-20x+97)
We add all the numbers together, and all the variables
5x-(-20x+97)-3=0
We get rid of parentheses
5x+20x-97-3=0
We add all the numbers together, and all the variables
25x-100=0
We move all terms containing x to the left, all other terms to the right
25x=100
x=100/25
x=4
Answer:
Equation 3
Step-by-step explanation:
An identity is, simply put, an equation that is always true. 1 = 1, 2 = 2, and x = x are all examples of identities, as there's no case in which 1 ≠ 1, 2 ≠ 2, and x ≠ x. Essentially, if we can manipulate and equation so that we end up with the same value on either side, we've found an identity. Let's run through and try to solve each of these equations to see which one fulfills that condition:
8 - (6v + 7) = -6v - 1
8 - 6v - 7 = -6v - 1
1 - 6v = -6v - 1
1 = -1
This is clearly untrue. Moving on to the next equation:
5y + 5 = 5y - 6
5 = -6
Untrue again. Solving the third:
3w + 8 - w = 4w - 2(w - 4)
2w + 8 = 4w - 2w + 8
2w + 8 = 2w + 8
If we created a new variable z = 2w + 8, we could rewrite this equation as
z = z, <em>which is always true</em>. We can stop here, as we've now found that equation 3 is an identity.
