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Anna35 [415]
3 years ago
11

Find ST if S(-3,10) and T(-2,3)

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0

Answer:

ST = 7.07 units

Step-by-step explanation:

* Lets explain how to find the length of a segment

- The length of a segment whose endpoints are (x_{1},y_{1})

  and (x_{2},y_{2}) can be founded by the rule of the distance

  d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

* Lets solve the problem

∵ The line segment is ST

∵ S is (-3 , 10)

∵ T is (-2 , 3)

- Assume that S is (x_{1},y_{1}) and T is (x_{2},y_{2})

∴ x_{1}=-3 and x_{2}=-2

∴ y_{1}=10 and y_{2}=3

- By using the rule above

∴ ST=\sqrt{(-2--3)^{2}+(3-10)^{2}}

∴ ST=\sqrt{(1)^{2}+(-7)^{2}}

∴ ST=\sqrt{1+49}

∴ ST=\sqrt{50}

∴ ST = 7.07 units

Oksana_A [137]3 years ago
5 0

Answer:

7.07 units

Step-by-step explanation:

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The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i
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Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.


Recall the formula for the sum of consecutive positive integers,

\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2

Now,

1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224

numbers, and their sum is

\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of 1+9\times2=19.

So, the sum of the first 1234 terms in the sequence is 2419.

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Step-by-step explanation:

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Please help and thank you
Flura [38]

Answer:

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