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kvasek [131]
4 years ago
10

7. Two bikes travelling in the same direction move at a speed of 30 km/hr. The bikes are separated by a distance of 5 km. What w

ould the speed of the car travelling in the opposite direction be if it meets these bikes at an interval of 4 minutes?
Physics
1 answer:
Fantom [35]4 years ago
6 0

Answer:

Explanation:

Call the bike on the right A

Call the bike on the left B

The car begins it's time when it passes A

4 minutes later, it passes B.

But B has moved in 4 minutes and that is the key to the problem.

How far has B moved.

t = 4 minutes = 4/60 hours = 1/15 of an hour.

d = ?

rate = 30 km / hr

d = r * t

d = 30 km/hr * 1/15 hours = 2 km

The distance between the bikes is 5 km.

So the car has traveled 5 - 2 = 3 km

d = 3 km

r = ?

t = 4 minutes = 1/15 hour

r = d/t = 3/(1/15)= 3 / 0.066666666  = 45 km/hr.

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Stolb23 [73]

Answer:

I = (1.80 × 10⁻¹⁰) A

Explanation:

From Biot Savart's law, the magnetic field formula is given as

B = (μ₀I)/(2πr)

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μ₀ = magnetic constant = (4π × 10⁻⁷) H/m

r = 3.6 cm = 0.036 m

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4π × 10⁻⁷ × I = 1.0 × 10⁻¹⁵ × 2π × 0.036

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Hope this Helps!!!

3 0
4 years ago
Help me find the natural logarithum of csch^-1 ((-1)/(2 sqrt(30)))
SVEN [57.7K]

The inverse hyperbolic cosecant of anything is a negative number.

In particular, csch⁻¹ [ (-1)/(2√30) ] = csch⁻¹ (≈ -0.0913) = ≈ -3.089

Whatever it is, negative numbers don't have logarithms.

3 0
4 years ago
It is known that heat is added to a gas in sealed container. The container is fitted with a moveable piston.
jasenka [17]

Answer:

d. Not enough information is given to answer this question.

Explanation:

From first law of thermodynamics

Q= W + ΔU

Q=Heat  ,W= Work , ΔU=Change in internal energy

If work done by the gas :

It means that W and Q both are positive

Q- W = ΔU

Ii Q > W ,then temperature of the gas will increase.

If  Q< W  ,Then temperature of the gas will decreases.

If work done on the gas:

Q positive but W will be negative

Q- W = ΔU

Q= W or Q>W  or Q< W ,then temperature of the gas will increase.

There are three cases because they did not give any information about the work.That is why option d is correct.

3 0
4 years ago
Two parallel wires separated by 3.55 cm repel each other with a force per unit length of 1.70 10-4 N/m. The current in one wire
Pepsi [2]

Explanation:

Given that,

Distance between two parallel wires, d = 3.55 cm

Force per unit length, F/L=1.7\times 10^{-4}\ N/m

Current in one wire, I = 4.8 A

(a) The force acting per unit length in the wire is given by :

\dfrac{F}{L}=\dfrac{\mu_oI_1I_2}{2\pi d}

Substituting all the values in above formula to find I₂ as:

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I_2=6.28\ A

(b) Since, it is given that the two conductors repel each other, it means that the current is flowing in opposite direction.

(c) If the direction of current is reversed, they will start attracting towards each other and it the one current is doubled, the force per unit length will gets doubled.

6 0
4 years ago
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