In my opinion, yes the bible tell us that "For God so loved<span> the world that he gave</span><span> his one and only Son,</span><span> that whoever believes</span><span> in him shall not perish but have eternal life"
So my answer is yes</span>
Answer:
B. 30 m down
Explanation:
In physics we have two types of quantities:
- Scalar quantity: it is a quantity which only has a magnitude (e.g: mass and time are scalar quantities, since they only have a magnitude)
- Vector quantity: it is a quantity which has both a magnitude and a direction (e.g: velocity is a vector quantity, since it has a magnitude (the speed) and a direction)
In this problem, we have:
A. 100 ounces of water --> scalar (this is a volume, which has only a magnitude)
B. 30 m down --> vector (this is a displacement, which has both a magnitude (30 m) and a direction (down)
C. 88 mi/s --> scalar (this is a speed, which has only a magnitude)
D. 45 gallons in a bucket --> scalar (this is a volume, which has only a magnitude)
So, the correct option is B.
I think the correct answer from the choices listed above is option A. The correct arrangement of the substances according to the <span>most to the least ordered particle arrangement should be wood, water and neon gas. Wood should be the first since it is solid which has the most ordered structure as compared to the liquid and a gas. The neon gas is the last since as a gas it has the least ordered structure.</span>
Answer:
Their final relative velocity is 0.190 m/s
Explanation:
The relative velocity of the satellites, v = 0.190 m/s
The mass of the first satellite, m₁ = 4.00 × 10³ kg
The mass of the second satellite, m₂ = 7.50 × 10³ kg
Given that the satellites have elastic collision, we have;


Given that the initial velocities are equal in magnitude, we have;
u₁ = u₂ = v/2
u₁ = u₂ = 0.190 m/s/2 = 0.095 m/s
v₁ and v₂ = The final velocities of the satellites
We get;


The final relative velocity of the satellite,
= v₁ + v₂
∴
= 0.095 + 0.095 = 0.190
The final relative velocity of the satellite,
= 0.190 m/s