The first step is splitting the atoms. Then there are control rods that absorb free floating nerons that are a result of fission. Next they heat they water pipe. Finally when they heat the pipe and water it turns to steam and they use it to harness energy!
A student tested a 0.1 M aqueous solution and made the
following observations conducts electricity, turns blue litmus to red and reacts
with Zn(s) to produce gas bubbles. The compound that could be the solute in
this solution is HBr. The answer is number 3.
The number of atoms N = 5.8 x 10²¹
<h3>Further explanation</h3>
A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12
1 mole = 6.02.10²³ particles
mass of N in 0.82 g of NaNO₃ (MW NaNO₃: 85 g/mol) :
moles of N :
The number of atoms N :
Answer:
A. 0.2395 w/w %
B. 2394ppm
Explanation:
A. To find concentrationin percent by mass of the solution we need to calculate mass of glycerol and mass of water. The formula is:
Mass glycerol / Total mass * 100
<em>Mass glycerol:</em>
The solution is 2.6x10⁻²moles / L. As there is 1L of solution there are 2.6x10⁻² moles of glycerol. In mass (Using molar mass glycerol: 92.09g/mol):
2.6x10⁻² moles of glycerol * (92.09g / mol) = 2.394g glycerol
<em>Mass of water:</em>
998.9mL and density = 0.9982g/mL:
998.9mL * (0.9982g/mL) = 997.1g of water.
That means percent by mass is:
% by mass: 2.394g / (997.1g + 2.394g) * 100 = 0.2395 w/w %
B. Parts per million are mg of glycerol per L of solution. As in 1L there are 2.394g. In mg:
2.394g * (1000mg / 1g) = 2394mg:
Parts per million: 2394mg / L = 2394ppm
Answer:
Mole percent of 
in solution is 1.71%
Explanation:
Number of moles of a compound is the ratio of mass to molar mass of the compound.
Molar mass of = 110.98 g/mol
Molar mass of 
= 18.02 g/mol
Density is the ratio of mass to volume
So, mass of 60.0 mL of water = 
Hence, 6.50 g of = 
of = 0.0586 moles of
60.8 g of = 
of = 3.37 moles of
So, mole percent of in solution = \frac{n_{CaCl_{2}}}{n_{total}}\times 100% = 
% = 1.71%
